An information system is crucial to the success of a business. Itemized below are five benefits of operating an information system in a business.
<h3>What are the benefits of an Information System?</h3>
Information systems are important because:
- They help to increase and enhance operational efficiencies such as accounting, sales, inventory, and HR operations.
- They help to minimize costs. As the business makes more and more informed decisions, its costs will drop.
- It enhances customer service. Information about customers helps the business to tailor its services to the requirements of each customer.
- Information system helps the decision-makers in the business to make better and more informed decisions.
- Information systems help to ensure business continuity.
<h3>What are the requirements for creating an information system?
</h3>
An information system requires the following:
- Hardware for the computer workstation and addendums
- Software
- A network communication amongst the computers and hardware
- a map of the company's processes and the people responsible for such processes
- A procedural manual.
- Existing data from the business.
For the barber's shop, for example, some of the components of the information system he must put in place are:
A workstation that collects information about:
- Clients
- Details of Sales
- Expenses
- Compliance dates and records etc.
Learn more about Information Systems at:
brainly.com/question/25226643
Stack is LIFO data structure (Last In First Out) where the last element entered in stack will be the last one to be out of stack. It has three operations: push() : used to insert an element in stack, pop() : used to delete an element from the stack, top() : used to return the top of the stack i.e. the newest member of the stack. All these operations will take place at the top.
<u>Explanation:</u>
Now, looking at the program, x and y are initialized the values of 2 and 3 respectively. The stack pushes 8 onto the stack making it the first member of the stack. Then the value of x which is 2 is pushed onto the stack. Next, (x+5) = (2+5) = 7 is pushed onto the stack.
Pop() is used to delete hence 7 is popped out from the stack. top() is assigned to y which is 2 in this case and again 2 is popped out from the stack. Now, (x+y) = (2+2) = 4 is pushed onto the stack. And the top() is assigned to x which is 4. 4 is again popped out from the stack. Hence the value of x is 4.
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