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LenaWriter [7]
3 years ago
6

A vessel of volume 100 cm3 contains 0.25 mol o2 and 0.034 mol co2 at 10.0c. Calculate the partial pressure of each component and

their total pressure
Chemistry
1 answer:
Artyom0805 [142]3 years ago
8 0

Answer: The partial pressure of oxygen is 76.56 atm , partial pressure of carbon dioxide is 10.44 atm and the total pressure is 87 atm.

Explanation:

According to the ideal gas equation:'

PV=nRT

P = Pressure of the gas = ?

V= Volume of the gas = 100cm^3=0.1L 1L=1000cm^3

T= Temperature of the gas = 10°C = 373 K      

R= Gas constant = 0.0821 atmL/K mol

n=  moles of gas= 0.25 +0.034 = 0.284 moles

P=\frac{nRT}{V}=\frac{0.284\times 0.0821\times 373}{0.1}=87atm

x_{O_2} = mole fraction of oxygen=\frac{\text {moles of }O_2}{\text {moles of }O_2+\text{moles of }CO_2}=\frac{0.25}{0.25+0.034}=0.88,  

x_{CO_2} =mole fraction of carbon dioxide=\frac{\text {moles of }CO_2}{\text {moles of }O_2+\text{moles of }CO_2}=\frac{0.034}{0.25+0.034}=0.12

partial pressure of oxygen = p_{O_2}=x_{O_2}\times P=0.88\times 87=76.56atm

partial pressure of carbon dioxide= p_{CO_2}=x_{CO_2}\times P=0.12\times 87=10.44atmatm

The partial pressure of oxygen is 76.56 atm , partial pressure of carbon dioxide is 10.44 atm and the total pressure is 87 atm.

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