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Helga [31]
3 years ago
8

Please help fast

Chemistry
1 answer:
Vilka [71]3 years ago
5 0

Moles of Oxygen they took in : C. 2.42

<h3>Further explanation</h3>

The gas equation can be written  

\large{\boxed{\bold{PV=nRT}}}

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08205 l.atm / mol K  

T = temperature, Kelvin  

P=1000 kPa

V = 6 L

T = 298 K

moles of Oxygen :

\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{1000\times 6}{8.31\times 298}\\\\n=2.42~moles

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Hello,

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