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3 years ago

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To get an idea how big a farad is, suppose you want to make a 1.0-F air-filled parallel-plate capacitor for a circuit you are bu

ilding. To make it a reasonable size, suppose you limit the plate area to 1.4 cm2 .
Part A
What would the gap have to be between the plates?
Express your answer using two significant figures and include the appropriate units.
Part B
Is this practically achievable?
Is this practically achievable?
a. yes
b. no

1 answer:

hichkok12 [17]3 years ago

5 0

Answer:

<em>The gap between the plates will be 1.2 x 10^-15 m</em>

<em>No, this is not practically achievable.</em>

Explanation:

Capacitance = 1.0 F

area of plate = 1.4 cm^2 = 1.4/10000 m^2 = m^2

distance = ?

We use the equation

$C$ = $\frac{A}{d}$ *ε

C is the capacitance

where A is the area

d is the distance of separation of plates

ε is the permeability of free space = 8.854×10^-12 F⋅m−1

substituting values, we have

1 = $\frac{0.00014}{d}$ * 8.854×10^-12

distance between plates = <em>1.2 x 10^-15 m</em>

<em>This is not practically achievable in real life</em>

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Answer:

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