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jok3333 [9.3K]
3 years ago
9

C) A sample of substance of volume 10 cm3 was brought back to Earth from the Moon.

Physics
1 answer:
postnew [5]3 years ago
3 0

Answer:

8125

Explanation:

P=0,13 N\\a=1,6 N/kg\\m=P/a=0,13/1,6=0,08125\\V=10(cm)^{3} =10^{-5} meters^{3}  \\p=m/V=0,08125/10^{-5} =0,08125*100000=8125kg/meters^{3}

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A brother and sister are standing next to each other at rest on a surface of frictionless ice. The brother’s mass is exactly twi
a_sh-v [17]

The sister suddenly pushes her brother. As a result, the sister moves with kinetic energy k. The resulting kinetic energy of the brother is k/2.

<h3>What is kinetic energy?</h3>

The ability of an object to do work by virtue of its motion is called the kinetic energy.

A brother and sister are standing next to each other at rest on a surface of frictionless ice. The brother’s mass is exactly twice that of his sister’s.

If the sister's mass is m, the brother's mass is 2m.

The kinetic energy of sister is k =1/2 mv²,

The velocity will also get halved for brother, So, the kinetic energy of brother will be

k' = 1/2 (2m)(v/2)²

On comparing, the relation between the kinetic energy of brother and sister is k' = k/2

Thus, the resulting kinetic energy of the brother is k/2.

Learn more about kinetic energy.

brainly.com/question/12669551

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2 years ago
What is the difference between transverse and longitudinal waves? Transverse waves always have greater frequencies than do longi
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6 0
3 years ago
A flywheel of J = 50 kg-m2 initially standing still is subjected to a constant torque. If the angular velocity reaches 20 Hz in
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Answer:

\tau = 1256.5\ N.m

Explanation:

given,

J = 50 kg-m²

frequency, f = 20 Hz

time ,t = 5 s

we know,

angular velocity = 2 π f

ω = 2 π x 20

ω = 125.66 rad/s

now, angular acceleration calculation

\alpha = \dfrac{\omega_f-\omega_i}{t}

\alpha = \dfrac{125.66-0}{5}

   α = 25.13 rad/s²

Torque given to the flywheel.

    \tau = I \alpha

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    \tau = 1256.5\ N.m

Torque of the given  flywheel is equal to \tau = 1256.5\ N.m

7 0
3 years ago
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