PSYCHOLOGY. neurons communicate with each other through ___

Suppose you pour water into a container until it reaches a depth of 12 cm. Next, you carefully pour in an 8.5 cm thickness of ol

Phantasy [73]

Answer:

the pressure at the bottom is approximately 103264 Pa

Explanation:

From Pascal's law, the pressure at the bottom of the container is the pressure from the atmosphere and the columns of water and olive , therefore

Pressure at the bottom = Pressure at the surface of the liquid ( atmospheric pressure) + pressure of the column of water + pressure of the column of olive oil

since

- Pressure at the surface of the liquid = atmospheric pressure = 101325 Pa

- pressure of the column of water = density of water * gravity * level of water

= 1000 kg/m³ * 9.8 m/s² * 0.12 m = 1176 Pa

- pressure of the column of olive oil= density of olive oil* gravity * level of olive oil = 916 kg/m³ * 9.8 m/s² * 0.085 m = 763 Pa

therefore

Pressure at the bottom = 101325 Pa + 1176 Pa + 763 Pa = 103264 Pa

density of olive oil was taken from internet sources ( we can check that is lower than the one of water, and thus it floats )

3 0

3 years ago

Please help!!! I have a physics exam tomorrow and I just can't wrap my head around this one!

Ainat [17]

The total electrostatic force on charge A is $28 \mu N$

Explanation:

The magnitude of the electrostatic force between two charges is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where:

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the two charges

r is the separation between the two charges

Here we have three positively charged particles A,B and C, located at the following positions:

$x_A = 0\\x_B = 10 m\\x_C = 20 m$

The magnitudes of the three charges are:

$q_A = q_B = q_C = 0.5 \mu C = 0.5\cdot 10^{-6}C$

The force exerted by B on A is to the left (because the force between two positive charges is repulsive), and the force exerted by C on A is also to the left (also repulsive). Therefore, the net force on A is just the sum of the two forces exerted by charges B and C:

$F_A = F_{BA} + F_{CA} = k\frac{q_B q_A}{(x_B-x_A)^2}+k\frac{q_C q_A}{(x_C-x_A)^2}=\\=(8.99\cdot 10^9) \frac{(0.5\cdot 10^{-6})^2}{(10)^2}+(8.99\cdot 10^9) \frac{(0.5\cdot 10^{-6})^2}{(20)^2}=2.8\cdot 10^{-5} N = 28 \mu N$

Learn more about electric force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

3 0

3 years ago

9.

julsineya [31]

I don’t know just needed points im sorry

8 0

3 years ago

I need the answer to this question please

Mandarinka [93]

Answer:

tanong mo kay gugel..wag dito nabobobo ako

6 0

3 years ago

Two positive charges of same magnitude are separated by some distance if we bring a unit positive charge from one charge to anot

Studentka2010 [4]

Answer:

Increases.

Explanation:

The electric potential increases when the two positive charges of same magnitude bring close to one charge to another because there is repulsive force between them due to same charge and when the two opposite charges move away from each other, the potential energy decreases. When two opposite charges are brought closer together, electric potential energy decreases while on the other hand, when we move opposite charges apart from each other than the work done against the attractive force that leads to an increase in electric potential energy.

3 0

3 years ago

PSYCHOLOGY. neurons communicate with each other through ____