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sp2606 [1]
3 years ago
9

Multiply the following ?

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
4 0

Answer:

\frac{3x^2}{x^2-6x-7}

Step-by-step explanation:

The first step is to find the multiplied out numerator and denominator, and then to simplify if possible. For the numerator, 3x*x=3x^2. For the denominator, (x+1)(x-7)=x^2-6x-7. This gives a final fraction of \frac{3x^2}{x^2-6x-7}. Hope this helps!

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What is the value of x to the nearest<br> tenth?
Colt1911 [192]

Answer:

C. 17.6

General Formulas and Concepts:

<u>Math</u>

  • Rounding

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Trigonometry</u>

  • [Right Triangles Only] SOHCAHTOA
  • [Right Triangles Only] tanθ = opposite over adjacent

Step-by-step explanation:

<u>Step 1: Identify Variables</u>

Angle θ = 40°

Opposite Leg = <em>x</em>

Adjacent Leg = 21

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute in variables [tangent]:                                                                   \displaystyle tan(40^\circ) = \frac{x}{21}
  2. [Multiplication Property of Equality] Isolate <em>x</em>:                                                \displaystyle 21tan(40^\circ) = x
  3. Rewrite:                                                                                                           \displaystyle x = 21tan(40^\circ)
  4. Evaluate:                                                                                                          \displaystyle x = 17.6211
  5. Round:                                                                                                            \displaystyle x \approx 17.6
6 0
2 years ago
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What is the simplified form of the expression? (b/7)^2
MakcuM [25]
(b/7)^2=(b/7)(b/7)=\frac{b^2}{49}
8 0
3 years ago
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What eigen value for this matix <br> (1 -2)<br> (-2 0)
natali 33 [55]

You find the eigenvalues of a matrix A by following these steps:

  1. Compute the matrix A' = A-\lambda I, where I is the identity matrix (1s on the diagonal, 0s elsewhere)
  2. Compute the determinant of A'
  3. Set the determinant of A' equal to zero and solve for lambda.

So, in this case, we have

A = \left[\begin{array}{cc}1&-2\\-2&0\end{array}\right] \implies A'=\left[\begin{array}{cc}1&-2\\-2&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right]=\left[\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right]

The determinant of this matrix is

\left|\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right| = -\lambda(1-\lambda)-(-2)(-2) = \lambda^2-\lambda-4

Finally, we have

\lambda^2-\lambda-4=0 \iff \lambda = \dfrac{1\pm\sqrt{17}}{2}

So, the two eigenvalues are

\lambda_1 = \dfrac{1+\sqrt{17}}{2},\quad \lambda_2 = \dfrac{1-\sqrt{17}}{2}

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3 years ago
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(Geometry HELP) The perimeter of WXY is ___ cm?
jeka57 [31]
I hope this helps you



QR=WS=2.93



RS=QW =2.04


QS=XR =2.28


RS=XQ=2.04



SY=QR =2.93


RY=QS =2.28


XY=XR+RY=2.28+2.28=4.56


XW=XQ+QW=2.04+2.04=4.08


WY=WS+SY=2.93+2.93=5.86


Perimeter of XYW=XW+WY+XY


Perimeter of XYW=4.08+5.86+4.56


Perimeter of XYW =14.5


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m= \frac{0-3}{-3-0}

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Point Slope Form:  (y-y1)=m(x-x1)

(y-3)=1(x-0)

(y-3)=(x-0)

(y-3)=(x)
6 0
4 years ago
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