Answer:
z= 3.63
z for significance level = 0.05 is ± 1.645
Step-by-step explanation:
Here p = 42% = 0.42
n= 500
We formulate our null and alternative hypotheses as
H0: p= 0.42 against Ha : p> 0.42 One tailed test
From this we can find q which is equal to 1-p= 1-0.42 = 0.58
Taking p`= 0.5
Now using the z test
z= p`- p/ √p(1-p)/n
Putting the values
z= 0.5- 0.42/ √0.42*0.58/500
z= 0.5- 0.42/ 0.0220
z= 3.63
For one tailed test the value of z for significance level = 0.05 is ± 1.645
Since the calculated value does not fall in the critical region we reject our null hypothesis and accept the alternative hypothesis that more than 42% people owned cats.
Hello
A. will be your answer.
Hoped This Helped! :D
1 - (1/5) = 4/5 yards of ribbon.
(4/5) / (1/10) = 8 Pieces of 1/10 Yard Long Ribbons
Hope that Helped you.
Answer:
x=-5
Step-by-step explanation:
6x+3+10=0
6x+30=0
6x=-30
x=-30/6
x=-5
-2x + 7y = 10 ⇒ -2x + 7y = 10
x - 3y = -3 ⇒ <u>-2x + 6y = 6 </u>
y = 4
-2x + 7(4) = 10
-2x + 28 = 10
<u> -28 -28</u>
<u>-2x</u> = <u>-18</u>
-2 -2
x = 9
(x, y) = (9, 4)
