We have to find the mass of the gold bar.
We have gold bar in the shape of a rectangular prism.
The length, width, and the height of the gold bar is 18.00 centimeters, 9.21 centimeters, and 4.45 centimeters respectively.
First of all we will find the volume of the gold bar which is given by the volume of rectangular prism:
Volume of the gold bar 
Plugging the values in the equation we get,
Volume of the gold bar 
Now that we have the volume we can find the mass by using the formula,
The density of the gold is 19.32 grams per cubic centimeter. Plugging in the values of density and volume we get:
grams
So, the mass of the gold bar is 14252.769 grams
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❖ The area is 169 square cm.
Find the value of each side (a square has 4 sides so divide by 4 ):
52/4 = 13
To find the area of a square, you only need 2 sides so multiply 2 sides:
13 x 13 = 139
Area = 139 square cm
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Step-by-step explanation:
log (√1000000x)
Rewrite √1000000x as (1000000x)1/2.
expand long ((1000000x)1/2) by moving 1/2
oby moving logarithm.
1/2 longth (1000000x)
Rewrite
log
(1000000x) as log(1000000)+log(x).
1/2(log(1000000)+log(x))
Logarithm base 10 of 1000000 is 6.
1/2(6+log(x))
Apply the distributive property.
1/2.6+1/2 log(x)
Cancel the common factor of 2.
3+1/2 long(x)
Combine 1/2 and log(x)
3+ long(x)/2
Answer:
Just move each point 17 units left, then 3 down. For example, for U, count seventeen points to the left, and once you are there, count 3 down. You should end up at (-7, 7). Do this for all the points.
Step-by-step explanation:
Hope this helps!
