Given:
D=165 feet and the frequency of the motion is 1.6 revolutions per minute.
Solution:
The radius is half of the diameter.
The radius of the wheel is 82.5 feet.
As we know: 
Substitute the value of T in the above formula.
If the center of the wheel is at the origin then for 
the rest position is 
.
This can be written as:
The actual height of the rider from the ground is:
The required equation is 
.
1. V = lwh
V = (8)(4)(5)
V = (32)(5)
V = 160 units³
2. V = lwh + lwh
V = (4)(2)(1) + (3)(1)(1)
V = (8)(1) + (3)(1)
V = 8 + 3
V = 11 units³
3. V = leh + s³
V = (9)(3)(4) + (3)³
V = (27)(4) + 27
V = 108 + 27
V = 135 units³
4. V = lwh
V = (3)(7)(2)
V = (21)(2)
V = 42 units³
The answer is: " 6.4 blocks " .
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3.2 blocks (one way), PLUS: 3.2 blocks the other way:
3.2 + 3.2 = 6.4 blocks .
or: (3.2) * 2 = 6.4 blocks .
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The answer is: " 6.4 blocks " .
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A. the first box is 7
the second box is 2
the third box is 100
the fourth box is 6.5
RULE: times 3 + 2
b. the first box is 45/2
the second box is -0.75
the third box is 0
the fourth box is 2.75
RULE: times 5/2
c. the first box is 1 1/2
the second box is 6
the third box is -4
the fourth box is -1.75
RULE: times half add one
