3 years ago

Which is the correct form for the quotient and remainder, written as partial fractions, of 3x^3-4x^2+5x-19/x^2+2x+3

Mathematics

1 answer:

Lapatulllka [165]3 years ago

8 0

Answer: it’s correct tyy

Step-by-step explanation:

You might be interested in

What is the next number in the pattern pattern below?

Varvara68 [4.7K]

The answer to this question is A. 31

3 0

3 years ago

Read 2 more answers

How many decimal places in 0.000894?

Sergio [31]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What is the converse of r->(~q v p)

alexira [117]

Answer:

$r => (\neg q \ \lor p) \ \equiv \ q \ \land \ \neg p => \neg r$

Step-by-step explanation:

In general, remember that the converse of $a => b$ is $\neg b => \neg a$ , therefore in this case $a = r \ \ , b = \neg q \ \lor p$

so $r => (\neg q \ \lor p) \ \equiv \ q \ \land \ \neg p => \neg r$

8 0

3 years ago

Can someone pLEASE HELP ASAPPPP<br> I NEED THIS TO FINISH PLEASE :p<br> THANNKS YOU !!

Goryan [66]

Answer: $5 for each eraser

Step-by-step explanation:

$5 in magazines ( 1 magazine )

? in erasers ( 4 erasers total )

$25 in total

step 1. 25-5= 20

step 2. 20/4= 5

step 3. $5 = each eraser (some expensive erasers)

6 0

2 years ago

Read 2 more answers

Simplify (square root 2)( square root of 2^3)

steposvetlana [31]

Answer:

$\large\boxed{(\sqrt2)(\sqrt{2^3})=4}$

Step-by-step explanation:

$(\sqrt2)(\sqrt{2^3})\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt{2\cdot2^3}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\sqrt{2^{1+3}}=\sqrt{2^4}\\\\(1)=\sqrt{2^{2\cdot2}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(2^2)^2}\qquad\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=2^2=4\\\\(2)=\sqrt{2\cdot2\cdot2\cdot2}=\sqrt{16}=6\ \text{because}\ 4^2=16$

8 0

3 years ago