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OverLord2011 [107]
10 months ago
7

A small publishing company is planning to publish a new book. The production cost will include one time fix costs (such as editi

ng) in variable cost (such as printing). There are two production methods it could use. One method, and one time fix cost will total $15,113, and the variable costs will be $22 per book. With the other method, The one time fixed costs will total $63,848, and the variable costs will be $10.75 per book. For how many books produced will the costs from the two methods be the same ? I NEED THIS ASAP !
Mathematics
1 answer:
icang [17]10 months ago
7 0

For the first method the fix cost is $ 15,113 and the variable cost is $ 22/book.

For the second method the fix cost is $ 63,848 and the variable cost is $ 10.75/book.

Let the number of books be <em>x</em> for which the cost from the two methods is same,

\begin{gathered} 15113+22x=63848+10.75x \\ 11.25x=48735 \\ x=4332 \end{gathered}

Thus, the required number of books is 4332.

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A survey of 9th and 10th graders was conducted to see which type of pet they
Studentka2010 [4]

Answer:

D 9/26

Step-by-step explanation:

Out of the 10th graders there are 104 total responses.  Knowing we only need data from 10th graders we can ignore everything else.  36/104 10th graders like cats and if you divide that by 4 you'll get the only possible answer of 9/26.  D 9/26 10th graders like cats.

6 0
3 years ago
Read 2 more answers
Find a linear equation whose graph is the straight line with the given property.
jeka57 [31]

Answer:

y = 3/4x - 9/8

Then read explanation and see here with 2 coordinates would make

if 3/4 = -6 then 1 = -8

y = -6x + c

-6 / 3/4  + 9/8 / - 0.5  = -2.25

therefore c = -2.25

y = -6x - 2.25

y = -6x - 9/4  and again 9/4 can be found easily if round up fraction decimal to 225/100 and divide by 4

Step-by-step explanation:

C1)    (0.5 , -0.75)

C2)   ( 1. -3.75)

y = mx + c

-3.75 - - 0.75  /   1 - 0.5  = -3.75 + 0.75 / 0.5

= -3 / 0.5 = m

m = -6

y = -6x + c

then this works given just one coordinate to solve for 1 or 2 sets given points

y - y1 = mx+c

y - - 0.75 =  0.75 (x - x1)

y + 0.75 = 0.75 (x - 0.5)

y + 0.75 = 0.75x - 0.375

y = 0.75 - 0.75   =  0.75x( - 0.375 - 0.75)

y = 0.75x -1.125

y = 3/4x - 9/8    as common denominators of 1125/1000 is 9/8 as we divide by  125 into the fraction as we start at 250 and check its half just like when finding common denominators we 1/4 the lower number and see if we can find its half or its double etc with the other num er as first step for 3sf numbers.

5 0
2 years ago
When Rafael emptied his pockets, e found he had a total of $3.50 in quarters and nickels. If he had 8 more quarters that nickels
jasenka [17]
You can use systems of equations for this one.

We are going to use 'q' as the number of quarters Rafael had,
and 'n' as the number of nickels Rafael had.


You can write the first equation like this:
3.50=0.05n+0.25q
This says that however many 5 cent nickels he had, and however many
25 cent quarters he had, all added up to value $3.50.
Our second equation is this:
q=n+8
This says that Rafael had 8 more nickels that he had quarters.

We can now use substitution to solve our system.

We can rewrite our first equation from:
3.50=0.05n+0.25q
to:
3.50=0.05n+0.25(n+8)

From here, simply solve using PEMDAS.

3.50=0.05n+0.25(n+8)     --Distribute 0.25 to the n and the 8
3.50=0.05n+0.25n+2     --Subtract 2 from both sides
1.50=0.05n+0.25n     --Combine like terms
1.50=0.30n     --Divide both sides by 0.30
5=n     --This is how many NICKELS Rafael has.

We now know how many nickels he has, but the question is asking us
how many quarters he has.

Simply substitute our now-known value of n into either of our previous
equations (3.50=0.05n+0.25q or q=n+8) and solve.

We now know that Rafael had 13 quarters.

To check, just substitute our known values for our variables and solve.
If both sides of our equations are equal, then you know that you have
yourself a correct answer.

Happy math-ing :)
5 0
3 years ago
A sqware has an area of 49 sqware feet. A rectangle has an area of 24 sqware feet its lanth is 2 feet longer than its width witc
PSYCHO15rus [73]

Answer:

Step-by-step explanation:

If the square has an area of 49 ft^2, then the length of one of its sides is

s = √(49 ft^2) = 7 ft, and its perimeter is P = 4(7 ft) = 28 ft.

As for the rectangle:  let W and L represent the width and length, respectively.  Then W*L = 24 ft^2 is the area.  L = W + 2 ft.  Therefore,

W(W + 2) = 24, or W^2 + 2W - 24 = 0, or (W +6)(W - 4) = 0.  Thus, W = 4 ft.

The perimeter of this rectangle is P = 2W + 2L, or

P = 2(4 ft) + 2(6 ft) = 24 ft.

The square has the larger perimeter:  It is 28 ft.

8 0
3 years ago
Two of the sides of a triangle are 7 inches
igomit [66]

Answer:

11 inches

Step-by-step explanation:

7^2+8^2=c^2

49+64=c^2

113=c^2

square root both side

c=10.63014581

round up and get c=11

hope this helped :)

8 0
3 years ago
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