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4 years ago

A scientist develops a new experiment to test atomic theory. His results do not agree with the theory.

Chemistry

1 answer:

mylen [45]4 years ago

8 0

Answer:

When the results of a new experiment to test atomic theory do not agree with the theory, scientist will repeat the experiment to make sure that his results are reliable.

Explanation:

In the scientific context, each new experiment must be performed with precision and following the steps of the scientific method.

An experiment that does not provide reliable data to demonstrate a theory must be reviewed in detail and performed again to confirm the data obtained in the first attempt.

A theory is a postulate that tries to explain a natural phenomenon, but whose argument can be discussed or does not have the acceptance of a law. When the theory is proven and there are no arguments against it, it can be universally accepted and becomes a law.

The other options are not valid due to:

Scientists worldwide will reject atomic theory because of the new results. A theory cannot be discarded without solid arguments or evidence in order to dismiss it and establish a new one.
The scientist will change his results to agree with the accepted theory. This would be an unethical procedure and unacceptable to the scientific community.
Other scientists will reject the results because they do not agree with the theory. The opinion of other scientists is not enough to dismiss a theory, if it has a valid scientific basis.

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When 1.550 g of liquid hexane (C6H14) undergoes combustion in a bomb calorimeter, the temperature rises from 25.87∘C to 38.13∘C.

AlladinOne [14]

Explanation:

1). The given data is as follows.

$T_{i} = 25.87^{o}C$ , $T_{f} = 38.13^{o}C$

C = 5.73 $kJ/^{o}C$

Hence, calculate the change in enthalpy of the reaction as follows.

$\Delta E_{rxn} = -C \times \Delta T$

= $-5.73 \times (38.13 - 25.87)^{o}C$

= -70.25 KJ

As, number of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{1.55}{(6 \times 12 + 14 \times 1)}$

= 0.018 mol

Therefore, enthalpy of reaction in kJ/mol hexane is as follows.

$\Delta E_{rxn} = \frac{-70.25 KJ}{0.018 mol}$

= $-3.90 \times 10^{3}$ kJ/mol

Thus, we can conclude that $\Delta E_{rxn}$ for the reaction in kJ/mol hexane is $-3.90 \times 10^{3}$ kJ/mol .

2). As we know that,

Number of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{1.55}{(7 \times 12 + 8 \times 1)}$

= 0.017 mol

$\Delta E_{rxn} = \E_{rxn} per mol \times \text{number of moles}$

= $-3.91 \times 10^{3} \times 0.017$

= -65.875 kJ

As, $\Delta E_{rxn} = C \times \Delta T
$

-65.875 kJ = $-C \times (37.57 - 23.12)^{o}C$

C = 4.56 $kJ/^{o}C$

Hence, heat capacity of the bomb calorimeter is 4.56 $kJ/^{o}C$ .

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Explanation:

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