Answer:
True
Explanation:because of the motion
Answer:
94.4g/mol is molar mass of the unknown
Explanation:
Based on the freezing point depression equation:
ΔT = Kf*m*i
<em>Where ΔT is the depression in freezing point (1.87°C)</em>
<em>Kf is freezing point depression constant of water (1.86°Ckg/mol)</em>
<em>And i is Van't Hoff factor (1 for nonelectrolyte solutes)</em>
<em />
Replacing:
1.87°C = 1.86°CKg/mol*m*i
1.005mol/kg solvent = m
Using the mass of the solvent we can find the oles of the nonelectrolyte:
1.005mol/kg solvent * 0.4764kg = 0.479moles
Molar mass is defined as the ratio between mass of a substance in grams and moles, that is:
45.2g / 0.479mol =
<h3>94.4g/mol is molar mass of the unknown</h3>
Answer:
Newton 3rd Law of Motion or the Law of Force Pairs
(An applied force)
Biomass and wood fuels generate combustion waste products of ash and greenhouse gasses. Greenhouse gasses are those gasses that trap the incoming infrared radiation from the sun and redistributes it in the earth's atmosphere. The primary greenhouse gas released in the combustion of these products is carbon dioxide.
Answer:
<em>a) The variable that we will change will be the different liquids.</em>
<em>b) The variable which will be kept same will be the ramp angle, the time for measuring in each experiment and the heat. </em>
Explanation:
In a scientific experiment, an independent variable is a variable which is changed by the researcher so that its effect on the dependent variable can be studied.
A dependent variable is a variable which is under study and might be influenced by changes in the independent variable.
It is best to study the effect of a single independent variable at a time so that we can easily infer the results.
<u><em>In the scenario discussed in the question, we would change the different liquids so that the time taken by each liquid to flow down the ramp can be studied.</em></u>
<u><em>We will keep the ramp angle, the time (of each experiment) and heat for each of the experiments the same so that a just conclusion can be drawn.</em></u>