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3 years ago

What is carbon in the lithosphere initially a part of before part of the burning of fossil fuel?

2 answers:

7 0

Carbon in the lithosphere is held in soil in the form of both organic and inorganic carbon which often as calcium carbonate. Carbon can leave the soil through soil respiration – which releases CO2, or by erosion – which can carry it into rivers or the ocean, where it then enters the hydrosphere.

aev [14]3 years ago

4 0

Answer:

The carbon in the lithosphere was initially found in the form of carbonate rocks. The formation of these carbonate rocks took place due to the deposition of the ancient marine plankton at the base of the ocean because of the activity of pressure and heat and got transformed into coal and petroleum.

The burning of fossil fuel, that is, the coal and petroleum gave rise to carbon dioxide, thus, it can be concluded that initially in the lithosphere the carbon prevailed in the form of carbonate rocks.

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A 1.10 g sample contains only glucose and sucrose. When the sample is dissolved in water to a total solution volume of 25.0L, th

olga_2 [115]

Answer:

$\large \boxed{79 \, \%}$

Explanation:

I assume the volume is 2.50 L. A volume of 25.0 L gives an impossible answer.

We have two conditions:

(1) Mass of glucose + mass of sucrose = 1.10 g

(2) Osmotic pressure of glucose + osmotic pressure of sucrose = 3.78 atm

Let g = mass of glucose

and s = mass of sucrose. Then

g/180.16 = moles of glucose, and

s/342.30 = moles of sucrose. Also,

g/(180.16×2.50) = g/450.4 = molar concentration of glucose. and

s/(342.30×2.50) = s/855.8 = molar concentration of sucrose.

1. Set up the osmotic pressure condition

Π = cRT, so

$\begin{array}{rcl}\Pi_{\text{g}} +\Pi_{\text{s}}&=&\Pi_{\text{tot}}\\\dfrac{g}{450.4}\times8.314\times298 + \dfrac{s}{855.8}\times8.314\times298 & = & 3.78\\\\5.501g + 2.895s & = & 3.78\\\end{array}$

Now we can write the two simultaneous equations and solve for the masses.

2. Calculate the masses

$\begin{array}{lrcl}(1)& g + m & = & 1.10\\(2) &5.501g +2.895s & = & 3.78\\(3) & m & = &1.10 - g\\&5.501g + 2.895(1.10 - g) & = & 3.78\\&2.606g + 3.185 & = & 3.78\\ &2.606g & = & 0.595\\(4) & g & = & \mathbf{0.229}\\&0.229 + s & = & 1.10\\& s & = & \mathbf{0.871}\\\end{array}$

We have 0.229 g of glucose and 0.871 g of sucrose.

3. Calculate the mass percent of sucrose

$\text{Mass percent} = \dfrac{\text{Mass of component}}{\text{Total mass}} \times \, 100\%\\\\\text{Percent sucrose} = \dfrac{\text{0.871 g}}{\text{1.10 g}} \times \, 100\% = 79 \, \%\\\\\text{The mixture is $\large \boxed{\mathbf{79 \, \%}}$ sucrose}$

6 0

3 years ago

How many different elements are in nine substances

Veronika [31]

You are made of mostly 6 elements: Oxygen, Carbon, Hydrogen, Nitrogen, Calcium, and Phosphorus. Some of these elements combine to form compounds in your body.

3 0

3 years ago

If the temperature of the earth's layers increases by about 90 degrees fahrenheit for every 1 mile from the surface and you are

bogdanovich [222]

The rate of change of the temperature of the Earth's surface is given to,
90°F/mile
To determine the temperature x miles away from the surface, we multiply the depth by the given rate. This will give us the answer of,
T = (90°F/mile)(90 mile)
= 8100°F
Thus, the temperature 90 miles deep in the Earth's surface is equal to 8100°F.

4 0

3 years ago

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The theoretical yield of a reaction is 75.0 grams of product and the actual yield is 42.0g. what is the percent yield? 75.0 56.0

Ronch [10]

I believe the percent yield is 56% if going by the formula of mass of actual yield/theoretical yield x 100%/

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4 years ago

Which form of energy represents a moving fan blades?!?!?

gregori [183]

Answer:

Mechanical I believe is the answer.