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Alona [7]
2 years ago
9

Under what conditions is a real gas closely approximated by an ideal gas?

Chemistry
1 answer:
ch4aika [34]2 years ago
7 0
Correct If not right, but, In low temperatures intermolecular forces also increase, since molecules move more slowly, similar to what would occur in a liquid state. Just remember that ideal gas behavior is most closely approximated in conditions that favor gas formation in the first place—heat and low pressure. me.
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Calculate the pH when 60.0 mL of 0.200 M HBr is mixed with 30.0 mL of 0.400 M CH₃NH₂ (Kb = 4.4 × 10⁻⁴).
Mariulka [41]

When a volume of 60.0 mL of 0.200 M HBr is mixed with a volume of 30.0 mL of 0.400 M CH3NH2, The pH value is mathematically given as

pH=10.64

<h3>What is the pH value when 60.0 mL of 0.200 M HBr is mixed with 30.0 mL of 0.400 M CH₃NH₂?</h3>

Question Parameters:

The pH when 60.0 mL of 0.200 M HBr

30.0 mL of 0.400 M CH₃NH₂ (Kb = 4.4 × 10^{-4}).

Generally, the equation for the Chemical Reaction  is mathematically given as

H Br + H_3C NH_2----- > CH_3 NH_3 Br

Therefore

oH=p^{kb}+-log\frac{salt}{base}

OH=-log(4.4*10^{-4})+\frac{0.1}{0.1}

OH=3.36

In conclusion, The equation pH value

pH+OH=14

Therefore

pH+=14-3.36

pH=10.64

Read more about Chemical Reaction

brainly.com/question/11231920

8 0
2 years ago
if one knows the mass and the molar mass of product D in a chemical reaction, one can determine the mass of product D procued by
ale4655 [162]

Answer:

Number of moles

Explanation:

Using the number of moles in chemical reactions, we can determine the quantity of products and even the reactants that are combining to form them.

The number of moles is derived using the expression below is;

     Number of moles  = \frac{mass}{molar mass}

Once we establish the number of moles of any of the specie given from the mass and molar mass, we can relate it to any other species.

7 0
3 years ago
Simón Bolívar and José de San Martín are figures associated with what event?
Jobisdone [24]

The event is South American independence. <u>Option D.</u>

<u />

By 1820, royalist Peru was an isolated outpost of Spanish influence. San Martin liberated Chile and Argentina to the south while Simon Bolivar and Antonio Jose de Sucre liberated Ecuador Colombia, and Venezuela to the north leaving only Peru and present-day Bolivia under Spanish control.

Simon Bolivar wrote two of his political treatises. The Manifesto de Cartagena Declaration of Cartagena and Carta de Jamaica Letters from Jamaica told the people of South America that Spain urged them to rebel against their colonial rule. Simon Bolivar is a Creole who grew up in a wealthy family. Bolivar devoted his time and effort to fight for Venezuela's independence from Spain. Bolivar was inspired by the Enlightenment ideas of John Locke.

Learn more about Simon Bolivar here:-brainly.com/question/1402690

#SPJ1

5 0
1 year ago
If 32.3 grams of KCl are dissolved in 192 grams of water, what is the concentration of the solution in percent by mass?
Likurg_2 [28]
The concentration is 0.168 g/ml
3 0
3 years ago
Read 2 more answers
(a) Calculate the mass of CaCl2·6H2O needed to prepare 0.125 m CaCl2(aq) by using 500. g of water. (b) What mass of NiSO4·6H2O m
Alinara [238K]

Answer:

(a) 13.7 g.

(b) 28.91 g.

Explanation:

  • molality (m) is the no. of moles of solute dissolved in 1.0 kg of solvent.

∴ m = (no. of moles of solute)/(mass of water (kg))

<em>∴ m = (mass/molar mass of solute)/(mass of water (kg)).</em>

<em />

<u><em>(a) Calculate the mass of CaCl₂·6H₂O needed to prepare 0.125 m CaCl₂(aq) by using 500. g of water.</em></u>

∵ m = (mass/molar mass of CaCl₂·6H₂O)/(mass of water (kg)).

m = 0.125 m, molar mass of CaCl₂·6H₂O = 219.0757 g/mol, mass of water = 500.0 g = 0.5 kg.

∴ 0.125 m = (mass of CaCl₂·6H₂O / 219.0757 g/mol)/(0.5 kg).

∴ mass of CaCl₂·6H₂O = (0.125 m)(219.0757 g/mol)(0.5 kg) = 13.7 g.

<u><em>(b) What mass of NiSO₄·6H₂O must be dissolved in 500. g of water to produce 0.22 m NiSO₄(aq)?</em></u>

∵ m = (mass/molar mass of NiSO₄·6H₂O)/(mass of water (kg)).

m = 0.22 m, molar mass of NiSO₄·6H₂O = 262.84 g/mol, mass of water = 500.0 g = 0.5 kg.

∴ 0.125 m = (mass of NiSO₄·6H₂O / 262.84 g/mol)/(0.5 kg).

∴ mass of NiSO₄·6H₂O = (0.22 m)(262.84 g/mol)(0.5 kg) = 28.91 g.

6 0
3 years ago
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