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3 years ago

A neutral atom with 6 electrons and 8 neutrons is an isotope of

Chemistry

1 answer:

andrey2020 [161]3 years ago

6 0

Answer:

It's an isotope of carbon

Explanation:

Isotopes have the same number of protons and electrons but a different number of neutrons.

Carbon, like we find it on the periodic table, has 6 electrons and protons and also 6 neutrons. ( Carbon has a standard molecular weight of 12: 6electrons + 6 neutrons)

This isotope has 6 electrons but 8 neutrons, so this represents Carbon-14. Which is an isotope of carbon.

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Name the following ionic compounds, keeping in mind that a transition metal cation must include its charge. ____________________

Lilit [14]

Answer :

(a) The name for $TiO_2$ is titanium(IV) oxide.

(b) The name for $BaCl_2$ is barium chloride.

(c) The name for $CuCl_3$ is copper(III) chloride.

(d) The name for $KI$ is potassium iodide.

(e) The name for $SrCl_2$ is strontium chloride.

(f) The name for $CuBr_2$ is copper(II) bromide.

Explanation :

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

Ionic compound are usually formed when a metal reacts with a non-metal.

The nomenclature of ionic compounds is given by:

1. Positive ion is written first.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

3. In case of transition metals, the oxidation state are written in roman numerals in bracket in-front of positive ions.

(a) $TiO_2$

$TiO_2$ is an ionic compound because titanium element is a metal and oxygen element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on tin is (+4) and the the charge on oxygen is (-2). Thus, the name for $TiO_2$ is titanium(IV) oxide.

(b) $BaCl_2$

$BaCl_2$ is an ionic compound because barium element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on barium is (+2) and the the charge on chlorine is (-1). Thus, the name for $BaCl_2$ is barium chloride.

(c) $CuCl_3$

$CuCl_3$ is an ionic compound because copper element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on copper is (+3) and the the charge on chlorine is (-1). Thus, the name for $CuCl_3$ is copper(III) chloride.

(d) $KI$

$KI$ is an ionic compound because potassium element is a metal and iodine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on potassium is (+1) and the the charge on iodine is (-1). Thus, the name for $KI$ is potassium iodide.

(e) $SrCl_2$

$SrCl_2$ is an ionic compound because strontium element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on strontium is (+2) and the the charge on chlorine is (-1). Thus, the name for $SrCl_2$ is strontium chloride.

(f) $CuBr_2$

$CuBr_2$ is an ionic compound because copper element is a metal and bromine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on copper is (+2) and the the charge on bromine is (-1). Thus, the name for $CuBr_2$ is copper(II) bromide.

3 0

3 years ago

Which of the following atoms forms an ionic bond with a sulfur atom? (Points : 3)

elena-s [515]

Ionic bonds are formed when there is complete transfer of valence electrons between two atoms.

Electronegativity tells the trend of an atom to atract electrons.

You should search for the complete set of rules that indicate whether an ionic or covalent bond happens.

There are two relevant rules to state if whether an ionic bond will happen:

- When the difference of electronegativities between the two atoms is greater than 2.0, then the bond is ionic.

- When the difference is between 1.6 and 2.0, the bond is ionic if one of the elements is a metal.

You need to list the electronegativities of the five elements (there are tables with this information)

Element electronegativity

Cu: 1.9
H: 2.2
Cl 3.16
I: 2.66
S: 2.58

Differences:

Cu / S: 2.58 - 1.9 = 0.68
H / S: 2.58 - 2.2 = 0.38
Cl / S: 3.16 - 2.58 =0.58
I / S: 2.66 - 2.58 = 0.08

Those differences are too low to consider that the bond is ionic.

Then the answer is that none of those atoms forms an ionic bond with sulfur.

8 0

3 years ago

Read 2 more answers

What volume of a 2.5 M NaOH solution is required to make 1 liter of a 0.75 M NaOH

defon

V1M1 = V2M2

<span>V1 × 2.5 = 1 × 0.75,
so V1 = 0.75/2.5
= 0.3 </span>

6 0

3 years ago

]According to Schrodinger's work with electrons and their orbital paths, what can be determined about the electrons of an atom?

kumpel [21]

Schrodinger developed a famous equation that allows the solutions for electron wave functions to be found given a specific potential. For the case of an atom, Schroginger's equation allows the determination of electron wave functions. These wave functions tell us how electrons are distributed in space around the atom.

3 0

3 years ago

How many molecules (not moles of nh3 are produced from 5.01×10?4 g of h2?

Irina-Kira [14]

2,02g ------- 6,02×10²³
5,01×10⁴g --- x

$x=\frac{5,01*10^{4}g*6,02*10^{23}}{2,02g}=14,93*10^{27}$

N₂ + 3H₂ ⇒ 2NH₃
1mol : 3mol : 2mol
18,06×10²³ : 12,04×10²³
14,93×10²⁷ : y

$y=\frac{14,93*10^{27}*12,04*10^{23}}{18,06*10^{23}}\approx9,95*10^{27}$

5 0

3 years ago