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Yuri [45]
3 years ago
15

What are two ways in which an ion could be nade

Chemistry
1 answer:
Bezzdna [24]3 years ago
3 0

Answer:

Ions are mainly formed by unstable elements by gaining or losing of electron(s) in the process of attaining there stability as they combine with other elements to form a bond.

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If gold gets hot enough it will melt, what type of change is this?
SashulF [63]
A.
Physical change
Step by step explanation;:)
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Calculate the amount of HCl in grams required to react with 3.75 g of CaCO3 according to the following reaction: CaCO3(s) + 2 HC
wolverine [178]

Answer:

The correct answer is 2.75 grams of HCl.

Explanation:

The given balanced equation is:  

CaCO₃ (s) + 2HCl (aq) ⇒ CaCl₂ (aq) + H₂O (l) + CO₂ (g)

Based on the given information, one mole of calcium carbonate is reacting with two moles of HCl. The molecular mass of HCl is 36.5 grams, thus, the mass of 2 moles of HCl will be, 36.5 × 2 = 73 grams

The molecular mass of CaCO₃ is 100 gram per mole, that is, the mass of 1 mole of CaCO₃ is 100 grams, therefore, the mass of HCl required for reacting with 3.75 grams of CaCO₃ will be,  

= 3.75 × 2 × 36.5 / 100 = 2.74 grams of HCl.  

8 0
3 years ago
EDTA EDTA is a hexaprotic system with the p K a pKa values: p K a1 = 0.00 pKa1=0.00 , p K a2 = 1.50 pKa2=1.50 , p K a3 = 2.00 pK
mihalych1998 [28]

Answer:

Check the explanation

Explanation:

When,

pH = -log[H+] = 3.30

[H+] = 5.0 X 10^{-4} M

Ka1 = 1 ; Ka2 = 0.0316 ; Ka3 = 0.01 ; Ka4 = 0.002 ; Ka5 = 7.4 X 10^{-7} ; Ka6 = 4.3 X 10^{-11}

alpha[Y^-4] = [H+]^6 + Ka1[H+]^5 + Ka1Ka2[H+]^4 + Ka1Ka2Ka3[H+]^3 + Ka1Ka2Ka3Ka4[H+]^2 + Ka1Ka2Ka3Ka4Ka5[H+] + Ka1Ka2Ka3Ka4Ka5Ka6

= 1.56 X 10^{-20} + 3.12 X 10^{-17} + 2 X 10^{-15} + 4 X 10^{-14} + 1.6 X 10^{-13} + 2.34 X 10^{-16} + 2 X 10^{-23}

= 2.02 X 10^{-13}

When,

pH = -log[H+] = 10.15

[H+] = 7.08 X 10^{-11} M

Ka1 = 1 ; Ka2 = 0.0316 ; Ka3 = 0.01 ; Ka4 = 0.002 ; Ka5 = 7.4 X 10^{-7} ; Ka6 = 4.3 X 10^-11

alpha[Y^{-4}] = [H+]^6 + Ka1[H+]^5 + Ka1Ka2[H+]^4 + Ka1Ka2Ka3[H+]^3 + Ka1Ka2Ka3Ka4[H+]^2 + Ka1Ka2Ka3Ka4Ka5[H+] + Ka1Ka2Ka3Ka4Ka5Ka6

= 1.26 X 10^{-61} + 1.8 X 10^{-51} + 8.1 X 10^{-43} + 1.12 X 10^{-34} + 3.17 X 10^{-27} + 3.3 X 10^{-23} + 1.83 X 10^{-23}

= 5.12 X 10^{-23}

4 0
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How to unscramble dtneinreigs
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Complete the table to summarize the properties of the different subatomic particles. Type in your answers.
Aloiza [94]

<h2>Complete the table to summarize the properties of the different subatomic particles. </h2>

Explanation:

Atom

It is a smallest particle which cant exist independently.

According To Dalton, atom was indivisible but later on, it was proved that atom can be subdivided into sub atomic particles called electron, proton & neutron.

These subatomic particles have marked properties .

Proton

  • It was discovered by E.Goldstein .
  • It is positively charged particle
  • It is present in nucleus .
  • Its mass is equal to 1.6726219 × 10⁻²⁷ kilograms

Neutron

  • It was discovered by E.chadwick .
  • It is neutral
  • It is present inside the nucleus .
  • It's mass is equal to 1.674927471×10⁻²⁷ kg

Electron

  • It was discovered by J.J Thomson .
  • It has negative charge .
  • It's mass is equal to 9.10938356 × 10⁻³¹ kilograms
  • It is present outside the nucleus in shells .
4 0
3 years ago
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