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Stella [2.4K]
3 years ago
15

On the basis of electronegativity, which of these pairs of elements is most likely to form monatomic ions?

Chemistry
2 answers:
mixer [17]3 years ago
8 0

Answer is: Cl and Na.

sodium and chlorine are in third period and they have very different properties. Sodium is solid metal and chlorine is gaseous nonmetal.

They form compound NaCl (Sodium chloride), because sodium lost one valence electron and form cation Na⁺, chlorine gain one electron and form anion Cl⁻.

Electron configuration of sodium atom: ₁₁Na 1s² 2s² 2p⁶ 3s¹.

Electron configuration of chlorine atom: ₁₇Cl 1s² 2s² 2p⁶ 3s² 3p⁵.

Other examples are metal-metal pairs and they do not form cation and anion.

tigry1 [53]3 years ago
3 0
"Cl and Na" is the one pair among the following choices given in the question that is most likely to form monatomic ions on the <span>basis of electronegativity. The correct option among all the options that are given in the question is the first option. I hope the answer has come to your great help.</span>
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A 25.0 mL aliquot of 0.0680 M EDTA was added to a 59.0 mL solution containing an unknown concentration of V3 . All of the V3 pre
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\mathbf{0.02 M}

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\text{So, from the given question:}

\text{EDTA will make complex with} V^{+3} \text{and the remaining EDTA will react with }Ga^{+3}

\text{Hence, the total concentration of} V^{+3} & Ga^{+3} \text{will be equivalent to EDTA concentration.}

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M_{EDTA} \times V_{EDTA} = ( V_{V^+3}\times M_{V^{+3}}+ V_{Ga^{+3} }\times M_{Ga^{+3}}})

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