Answer:
google
Explanation:
go to the plus thing on your screen and search it. (please dont attack me im doing a dare >:( )
Answer:
0.053moles
Explanation:
Hello,
To calculate the number of moles of gas remaining in his after he exhale, we'll have to use Avogadro's law which states that the volume of a given mass of gas is directly proportional to its number of moles provided that temperature and pressure are kept constant. Mathematically,
V = kN, k = V / N
V1 / N1 = V2 / N2= V3 / N3 = Vx / Nx
V1 = 1.7L
N1 = 0.070mol
V2 = 1.3L
N2 = ?
From the above equation,
V1 / N1 = V2 / N2
Make N2 the subject of formula
N2 = (N1 × V2) / V1
N2 = (0.07 × 1.3) / 1.7
N2 = 0.053mol
The number of moles of gas in his lungs when he exhale is 0.053 moles
Answer:
2 CH₃OH + 3 O₂ ⇒ 2 CO₂ + 4 H₂O
Explanation:
Methanol is CH₃OH. Oxygen is O₂. A combustion produces CO₂ and H₂O. Create an equation using this information and balance.
CH₃OH + O₂ ⇒ CO₂ + H₂O
2 CH₃OH + 3 O₂ ⇒ 2 CO₂ + 4 H₂O
Answer : The correct option is, (C) ΔS (surroundings) = 100 J/K
Explanation :
As we know that:
ΔS (total) = ΔS (system) + ΔS (surroundings)
When the reaction is spontaneous ΔS (total) > 0 , that means positive value.
When the reaction is non-spontaneous ΔS (total) < 0 , that means negative value.
As we are given that:
ΔS (system) = -100 J/K (for spontaneous reaction)
Thus, the ΔS (surroundings) must be greater than ΔS (system) that means positive value.
So, ΔS (surroundings) = 100 J/K
Hence, the correct option is, (C) ΔS (surroundings) = 100 J/K
