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storchak [24]
4 years ago
15

How do I calculate the sum of 6.078 g and 0.3329 g ?

Chemistry
1 answer:
Vesnalui [34]4 years ago
8 0
The answer is 6.4109 grams
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What is the molar mass of a gas with a density of 3.50 g/L at a
Kruka [31]

Answer:

  • <u>104 g/mol</u>

Explanation:

Use the ideal gas equation:

      pV=nRT

Where:

  • p is pressure: 0.950atm
  • V is volume: unknown
  • n is number of moles: unknown
  • R is the universal constat of gases: 0.08206 atm.liter/ (K.mol)
  • T is the absolute temperature: 345K

Use the <em>molar mass</em> of the gas to include the density in the formula:

  • molar mass = mass in grams / number of moles

  • ⇒ mass in grams = number of moles × molar mass

  • density = mass in grams / volume

  • ⇒ density = number of moles × molar mass / volume

  • density = (n/V) × molar mass

  • ⇒ n/V = density / molar mass

Clear n/V from the gas ideal equation and subsittute with density/molar mass:

  • n/V = p/(RT)
  • density / molar mass = n/V
  • density/molar mass = p/(RT)
  • molar mass = density × RT / p

Now you can subsitute the data:

molar mass = (3.50g/liter) × 0.08206 atm.liter/(K.mol) × 345K / 0.950 atm

  • molar mass = 104.3 g/mol

  • Round to the nearest whole number: 104g/mol ← answer
3 0
3 years ago
Drag each tile to the correct location in the Venn diagram.
notka56 [123]

Answer:

Other comparisons of the legislative process in both chambers shows that:

In both House and Senate: Committees review and mark up bills.

In the House of Representatives: Bills are introduced by the reading clerk.

In Senate: Bills can be filibustered.

In Senate: Only related amendments can be attached to bills.

In both House and Senate: Unrelated riders can be attached to bills.

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4 0
2 years ago
An area with an average annual temperature of more than 64°F and greater than 59 inches of annual rainfall would be an example o
aalyn [17]

Answer:

Based on the temperature and rainfall, it is the tropical

5 0
3 years ago
Read 2 more answers
Electronic transitions (i.e., absorption of uv or visible light) of the conjugated molecule butadiene can be approximated using
dlinn [17]

Answer:

2.51 Angstroms

Explanation:

For a particle in a one dimensional box, the energy level, En, is given by the expression:

En = n²π² ħ² / 2ma²

where n is the energy level, ħ²  is Planck constant divided into 2π, m is the mass of the electron ( 9.1  x 10⁻³¹ Kg ), and a is the length of the one dimensional box.

We can calculate  the change in energy, ΔE, from n = 2 to n= 3  since we know the wavelength of the transition  ( ΔE = h c/λ ) and then substitute this value for the expresion of the ΔE for a particle in a box and solve for the  length a.

λ = 207 nm x 1 x 10⁻⁹ m/nm = 2.07 x 10⁻⁷ m      ( SI units )

ΔE = 6.626 x 10⁻³⁴ J·s x  3 x 10⁸ m/s  / 2.07 x 10⁻⁷ m

ΔE   = 9.60 x 10⁻¹⁹ J

ΔE(2⇒3) = ( 3 - 2 )  x  π² x ( 6.626 x 10⁻³⁴ J·s / 2π )² / ( 2 x 9.1 x 10⁻³¹ Kg x a² )

9.60 x 10⁻¹⁹ J  =  π² x( 6.626 x 10⁻³⁴ J·s / 2π )² / ( 2 x 9.1 x 10⁻³¹ Kg x a² )

⇒ a = 2.51 x 10⁻¹⁰ m

Converting to Angstroms:

a = 2.51 x 10⁻¹⁰ m x 1 x 10¹⁰ Angstrom / m = 2.51 Angstroms

6 0
4 years ago
63.5 grams of alcohol having a density of 0.818 g/ml are require for a chemical reaction. How many milliliters of alcohol should
damaskus [11]
Mass = 63.5 grams

density = 0.818 g/mL

D = m / V

0.818 = 63.5 / V

V = 63.5 / 0.818

V = 77.628 mL

hope this helps!
8 0
3 years ago
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