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77julia77 [94]
3 years ago
7

A rectangular sheep pen measures 5 m long and 9 m wide. The perimeter of the cow pen is double the perimeter of the sheep pen wh

at is the perimeter of the cow pen?
Mathematics
2 answers:
Nastasia [14]3 years ago
8 0

Answer:

56

Step-by-step explanation:

5×2 +9×2=28

28 × 2 =56

saw5 [17]3 years ago
3 0

Answer:

56m

Step-by-step explanation:

First calculate the perimeter of the sheep pen.

The perimeter is all the side lengths added together.

The rectangle has two sides that are 5m long and two sides that are 9m long.

5 + 5 + 9 + 9 = 28m

Now that you know the perimeter of the sheep pen you can double it by multiplying by 2 to find tha perimeter of the cow pen.

28 * 2 = 56m

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Answer:

90°-43°=47°

Step-by-step explanation:

complementary is two angles added up to 90 degrees

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3 years ago
What is the median of the data?<br><br> 11,16,12,7,23,9,5,5
Stells [14]

Answer:

5,5,7,*9,11,*12,16,23

Step-by-step explanation:

Since, the data has an even amount of numbers once, you put your numbers in order you place your pointer fingers from the 1st to last number & continue to move closer. There is an even amount of numbers so you would have to add the 2 numbers up & then divide them by 2.

9+11=20 divided by 2=10

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3 years ago
Please help me out with this question
julsineya [31]
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3 years ago
NEED HELP PLZ
skad [1K]

Answer:

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5 0
3 years ago
Read 2 more answers
A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a
zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}

Hence the answer is 0.1157

(ii) None is defective becomes

\begin{gathered} \lparen\frac{5}{6})^4=\frac{625}{1296} \\ =0.4823 \end{gathered}

hence the answer is 0.4823

(iii) All are defective

\begin{gathered} \lparen\frac{1}{6})^4=\frac{1}{1296} \\ =0.00077 \end{gathered}

(iv) At least one is defective

This is 1 - probability that none is defective

\begin{gathered} 1-\lparen\frac{5}{6})^4 \\ =1-\frac{625}{1296} \\ =\frac{671}{1296} \\ =0.5177 \end{gathered}

Hence the answer is 0.5177

3 0
1 year ago
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