Given that
z₁ = 15 (cos(90°) + i sin(90°))
z₂ = 3 (cos(10°) + i sin(80°))
we get the quotient z₁/z₂ by dividing the moduli and subtracting the arguments:
z₁/z₂ = 15/3 (cos(90° - 10°) + i sin(90° - 10°))
z₁/z₂ = 5 (cos(80°) + i sin(80°))
so that z₁ is scaled by a factor of 1/3 and is rotated 10° clockwise.
Step-by-step explanation:
plug the coordinate points into the equations and solve for the remaining variable.
b) (2,3) - 5(2) + b(3) = 16
10 + 3b = 16. 3b= 6. b = 2
(0,8) - 5(0) + 2(8) = 16. 0+ 16 = 16. ☆
a) (4,4) assume based on results you meant y squared. (y^2)
(4)^2 = 4k. 16 = 4k. k = 4
(8)^2 = 4(16). 64 = 64. ☆
68.40 divide 6 = 11.4
41.80 divided 4= 10.45
Plan B is lower fee per lesson
It's -5/2,-4 is right. ok?
By cutting each corner we have that the resulting dimensions are:
27 - 2x
18 - 2x
Height = x
Therefore, the volume of the box in terms of the variable x, is given by:
V (x) = (x) * (27-2x) * (18-2x)
Answer:
The volume of the box in terms of x is:
(27-x) (18-x) x
