Let's name the number 'n'. Now write an equation. 7*n +n^2 =12Now you can form a quadratic. n^2 +7n-12=0. Now you can use a myriad of methods to solve it. If you still need help, just message me.
Step-by-step explanation:
14 gallons bought for $34.72
1 gallon bought for

=$2.48
Answer:
If you need the equation: 10x - 12
If you need the equation more simplified: x - 1.2
Step-by-step explanation:
(2x + 7) - (8x + 5)
Move the parts of the equation around
(2x + 8x) - (7 + 5)
Add 2x and 8x together
10x - (7 + 5)
Add 7 and 5 together
10x - 12
If you need it even more simplified, continue
10x - 12
Divide by 10
x - 12/10
Simplify
x - 1.2
I Hope That This Helps! :)
Y'sinx=ylny, is equivalent to <span>dy / dx (sinx=ylny, and </span><span>dy sinx=ylny dx
it is similar to dy/</span>ylny = dx/sinx
so integral (dy/ylny = integral dx/sinx)
integral dx/sinx)= Ln{abs value ( tan(x /2 + pi /4)}
integral (dy/ylny= ln(lny)
final answer is lny = {abs value ( tan(x /2 + pi /4)}+C, you can find y, or x
Answer:
The values of x for which the model is 0 ≤ x ≤ 3
Step-by-step explanation:
The given function for the volume of the shipping box is given as follows;
V = 2·x³ - 19·x² + 39·x
The function will make sense when V ≥ 0, which is given as follows
When V = 0, x = 0
Which gives;
0 = 2·x³ - 19·x² + 39·x
0 = 2·x² - 19·x + 39
0 = x² - 9.5·x + 19.5
From an hint obtained by plotting the function, we have;
0 = (x - 3)·(x - 6.5)
We check for the local maximum as follows;
dV/dx = d(2·x³ - 19·x² + 39·x)/dx = 0
6·x² - 38·x + 39 = 0
x² - 19/3·x + 6.5 = 0
x = (19/3 ±√((19/3)² - 4 × 1 × 6.5))/2
∴ x = 1.288, or 5.045
At x = 1.288, we have;
V = 2·1.288³ - 19·1.288² + 39·1.288 ≈ 22.99
V ≈ 22.99 in.³
When x = 5.045, we have;
V = 2·5.045³ - 19·5.045² + 39·5.045≈ -30.023
Therefore;
V > 0 for 0 < x < 3 and V < 0 for 3 < x < 6.5
The values of x for which the model makes sense and V ≥ 0 is 0 ≤ x ≤ 3.