8, 9 you basically just evaluate the equation in the parentheses
You have to use implicit derivative
dy / dx = y'
xy^3+y=3x
y^3 + 3xy^2 y' + y' = 3
[3xy^2 + 1) y'= 3 - y^3
3 - y^3
y' = ----------------- <-----------answer
3xy^2 + 1
1. it’s saying 2-6 which is -4
2. it’s saying -6-5 which is -11
