The sum of 4 consecutive intergers is 50, what is the first interger in this relationship
1 answer:
Answer:
x = 11
Step-by-step explanation:
Consecutive means in a row
Let x be the first integer
x+1 is the second
x+2 is the third
x+3 is the 4th
The sum is 50
x+ x+1 + x+2 + x+3 = 50
Combine like terms
4x+6 = 50
Subtract 6 from each side
4x+6-6 = 50-6
4x = 44
Divide each side by 4
4x/4 = 44/4
x = 11
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Answer:
x=−5
Step-by-step explanation:
x+12=7
Step 1: Subtract 12 from both sides.
x+12−12=7−12
x=−5
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