The sum of 4 consecutive intergers is 50, what is the first interger in this relationship
1 answer:
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Answer:
a
Step-by-step explanation:
Solving the inequality
>
+ 1
Multiply through by 12 ( the LCM of 6 and 4 ) to clear the fractions
2(x + 3) > 3x + 12
2x + 6 > 3x + 12 ( subtract 2x from both sides )
6 > x + 12 ( subtract 12 from both sides )
- 6 > x , that is
x < - 6
The only value less than - 6 is - 10
Thus x = - 10 is a solution to the inequality