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2 years ago

Find the value of x Please help , thanks

Mathematics

1 answer:

nadezda [96]2 years ago

4 0

Answer:

Approx : 14.0294372515

Step-by-step explanation:

There are 2 congruent right triangles in this trapezoid. The hypotenuse and adjacent side lengths are 19 and 17 respectively. Using the Pythagorean Theorem, 19^2-17^2 is 72. The square root of 72 is approximately 8.48528137424. That is the length of the portions on the bottom that don't include the length x. 8.48528137424*2 is approximately 16.9705627485. 31-16.9705627485 gives you the length of the side x.

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A car travels 26 1/2 miles in 45 minutes what is the car rate of speed in miles per hour

Dimas [21]

Answer and work in picture.

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3 years ago

How can the scaling of a line graph be used to mislead a reader?

Anna [14]

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2 years ago

1. f(x) = x2 - 21 f(5)

matrenka [14]

Answer:

x=13

Step-by-step explanation:

if you will substitute the value of f(x) with 5, you will get the following equation:

5=2x-21

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x=13

(I didn't know what you ment when you wrote x2, is it x square or 2X)

I really hope it was the second one, cause that's how I solved it.

8 0

2 years ago

A circle has the equation 2x²+12x+2y²−16y−150=0.

KonstantinChe [14]

Answer: B. The coordinates of the center are (-3,4), and the length of the radius is 10 units.

Step-by-step explanation:

The equation of a circle in the center-radius form is:

$(x-h)^{2} +(y-k)^{2}=r^{2}$ (1)

Where $(h,k)$ are the coordinates of the center and $r$ is the radius.

Now, we are given the equation of this circle as follows:

$2x^{2}+12x+2y^{2}-16y-150=0$ (2)

And we have to write it in the format of equation (1). So, let's begin by applying common factor 2 in the left side of the equation:

$2(x^{2}+6x+y^{2}-8y-75)=0$ (3)

Rearranging the equation:

$x^{2}+6x+y^{2}-8y=75$ (4)

$(x^{2}+6x)+(y^{2}-8y)=75$ (5)

Now we have to complete the square in both parenthesis, in order to have a perfect square trinomial in the form of $(a\pm b)^{2}=a^{2}\pm+2ab+b^{2}$ :

For the first parenthesis:

$x^{2}+6x+b^{2}$

We can rewrite this as:

$x^{2}+2(3)x+b^{2}$

Hence in this case $b=3$ and $b^{2}=9$ :

$x^{2}+2(3)x+3^{2}=x^{2}+6x+9=(x+3)^{2}$

For the second parenthesis:

$y^{2}-8y+b^{2}$

We can rewrite this as:

$y^{2}-2(4)y+b^{2}$

Hence in this case $b=-3$ and $b^{2}=9$ :

$y^{2}-2(4)y+4^{2}=y^{2}-8y+16=(y-4)^{2}$

Then, equation (5) is rewritten as follows:

$(x^{2}+6x+9)+(y^{2}-8y+16)=75+9+16$ (6)

Note we are adding 9 and 16 in both sides of the equation in order to keep the equality.

Rearranging:

$(x-3)^{2}+(y-4)^{2}=100$ (7)

At this point we have the circle equation in the center radius form $(x-h)^{2} +(y-k)^{2}=r^{2}$

Hence:

$h=-3$

$k=4$

$r=\sqrt{100}=10$

8 0

3 years ago

Explain it hank needs 3 quarters to play one video game each time.if he has 14 quarters, how many timed can he play? Explain.

ratelena [41]

The answer is is 4 times. 
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6 0

2 years ago