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goldfiish [28.3K]
3 years ago
9

Jada has some pennies and dimes. The ratio of Jada's pennies to dimes is 2 to 3. From the information given, can you determine h

ow many coins Jada has? If Jada has 55 coins, how many of each kind of coin does she have?
Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
4 0

Answer:

No, we can't determine how many coins Jada has.

She will have 22 pennies and 33 dimes.

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Which statement is true about 143? A. It is a prime number. B. It is a composite number. C. It is a whole number that is neither
Stels [109]

Answer:

B. It is a composite number.

Step-by-step explanation:

143 can be divided by 11 and 13 making it a composite number.

5 0
3 years ago
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Find the surface area of the right prism. Round to the nearest whole number.
andriy [413]

Answer:

\large\boxed{S.A.=96\ cm^2}

Step-by-step explanation:

We have:

(1) two trapezoids with bases b₁ = 7cm and b₂ = 5cm and the height h = 4cm

(2) three rectangles 3 cm × 7 cm, 3 cm × 4 cm and 3 cm × 5 cm.

The formula of an area of a trapezoid:

A=\dfrac{b_1+b_2}{2}\cdot h

Substitute:

A=\dfrac{7+5}{2}\cdot4=24\ cm^2

Calculate the areas of the rectangles:

A_1=(3)(7)=21\ cm^2\\\\A_2=(3)(4)=12\ cm^2\\\\A_3=(3)(5)=15\ cm^2

The Surface Area:

S.A.=(2)(24)+21+12+15=96\ cm^2

5 0
3 years ago
The expression x^4-16 is equivalent to the product of (x+2) and p(x) which expression could represent p(x)
bagirrra123 [75]
Easy
differnce of 2 perfect squares
a²-b²=(a+b)(a-b)

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x⁴=(x²)²
16=4²

(x²)²-4²=(x²+4)(x²-4)
x²-4 can be factored since 4=2²
x²-2²=(x+2)(x-2)

complete factored form is
(x²+4)(x+2)(x-2)
gegroup to seperate (x+2)
(x+2)[(x²+4)(x-2)]
(x+2)p(x)

p(x)=(x²+4)(x-2)
expanded
p(x)=x³-2x²+4x-8
3 0
3 years ago
What is the area of the shaded shape and I need the steps
vesna_86 [32]
Area of a triangle: 1/2 of area*height
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144 - 32 = 112 inches squared.
The triangles aren't shaded, so you can subtract them from the area of the rectangle to get the shaded area. The answer is 112 inches squared.
7 0
3 years ago
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Answer:

30

Step-by-step explanation:

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