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vlada-n [284]
3 years ago
10

What is the quotient of 1/8 divided by 4/9

Mathematics
1 answer:
kifflom [539]3 years ago
3 0

You would want to use the Keep, Change , Flip

method. So you keep the 1/8, change division into multiplication, the flip the 4 into 1/4.

Step-by-step explanation:

(1/8) / 4

(1/8) * (1/4)

answer: 1/32 or 0.03125

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Identify the property that is illustrated. <br> 23 + (2 +7) = (23 +2) + 7
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That property would be associative

Step-by-.step explanation:

Because no matter how you change the parentheses in that problem, it would be the same.

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Find the missing angels in the parallelogram
krek1111 [17]

Answer:

m<B = 60°

m<C = 60°

m<F = 80°

m<G = 80°

Step-by-step explanation:

m<B = 180° - 120° = 60°

m<C = m<B = 60° (Vertically opposite angles are equal)

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6 0
3 years ago
Brock exercises every day. The function E = 15m + 5 represents the number of sit-ups he can do in m minutes. After drinking a ne
adoni [48]

Answer:

S=45m+15

Step-by-step explanation:

we have

E------>the number of sit-ups

m---->  the time in minutes

S----> the number of sit-ups after drinking the sports drink

E=15m+5 ----> equation A

S=3E ----> equation B

substitute the equation A in the equation B

S=3(15m+5)

S=45m+15

7 0
2 years ago
Root 3 cosec140° - sec140°=4<br>prove that<br><br>​
Lorico [155]

Answer:

Step-by-step explanation:

We are to show that \sqrt{3} cosec140^{0} - sec140^{0} = 4\\

<u>Proof:</u>

From trigonometry identity;

cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}

\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\

From trigonometry, 2sinAcosA = Sin2A

= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\=  \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\=  \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2  \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}

Also note that sin(B-C) = sinBcosC - cosBsinC

sin420cos140 - cos420sin140 = sin(420-140)

The resulting equation becomes;

\frac{4(sin(420-140)) }{sin280}

= \frac{4sin280}{sin280}\\ = 4 \ Proved!

3 0
3 years ago
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