Question

Which expression is equivalent to (3m^-1n^2)^4/(2m^-2n)^3? Assume M does not equal 0 and does not equal 0.

Answer 1

Answer:

$\frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}$ $=\frac{81m^{2}n^{5}}{8}$

Step-by-step explanation:

$\frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}$

$=\frac{(3^4m^{-4}n^8)}{2^3m^{-6}n^3}$

$=\frac{(3^4m^{-4+6}n^{8-3})}{2^3}$

$=\frac{3^4m^{2}n^{5}}{2^3}$

$=\frac{81m^{2}n^{5}}{8}$