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oee [108]
3 years ago
12

Determine the centripetal force on a vehicle rounding a circular curve with a radius of 80 m at a constant speed of 90 km/h if t

he vehicle's mass is 2,000 kg. (Hint: First express the velocity in meters per second)
Physics
1 answer:
quester [9]3 years ago
3 0
Mass of the vehicle = 2000 kg
Velocity of the vehicle = 90 km/hr
                                   = 25 m/s
Radius of the curve = 80 m
Then
Centripetal force = [2000 * (25)^2]/80
                            = (2000 * 625)/80
                            = 15625 kg m/s
                            = 15625 Newton second
I hope that this is the answer that you were looking for and the answer has come to your desired help. 
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A mass of 100 g stretches a spring 5 cm. If the mass is set in motion from its equilibrium position with a downward velocity of
Rudiy27

Answer:

Explanation:

Given

mass of spring m=100\ gm

extension in spring x=5\ cm

downward velocity v=70\ cm/s

Position in undamped free vibration is given by

u(t)=A\cos \omega _0t+B\sin \omega _0t

where \omega _0^2=\frac{k}{m}

also \frac{k}{m}=\frac{g}{L}

\omega _0^2=\frac{k}{m}=\frac{9.8}{0.05}

\omega _0=14

u(t)=A\cos(14t)+B\sin(14t)

it is given

u(0)=0

u'(0)=70\ cm/s

substituting values we get

A=0

u(t)=B\sin (14t)

u'(t)=14B\cos (14t)

70=14B

B=\frac{10}{2}

B=5

u(t)=5\sin (14t)

3 0
3 years ago
Why would a flat sheet of paper and a wad of paper with the same mass not fall through the air at the same rate?
Gelneren [198K]
The flat sheet of paper has more surface area than the crumpled ball
7 0
3 years ago
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A 50g ball is released from rest 1.0 above the bottom of thetrack
ludmilkaskok [199]

Answer:

The maximum height of the ball is 2 m.

Explanation:

Given that,

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Angle = 30°

The equation is

y=\dfrac{1}{4}x^2

We need to calculate the velocity

Using conservation of energy

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Here, ball at rest so initial kinetic energy is zero and at the bottom the potential energy is zero

\Delta U_{i}=\Delta K_{f}

Put the value into the formula

mgh=\dfrac{1}{2}mv^2

Put the value into the formula

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v=\sqrt{19.6}

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We need to calculate the maximum height of the ball

Using again conservation of energy

\dfrac{1}{2}mv^2=mgh

Here, h = y highest point

Put the value into the formula

\dfrac{1}{2}\times50\times10^{-3}\times(4.42)^2=50\times10^{-3}\times9.8\times h

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y=\dfrac{1}{4}x^2

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4 0
3 years ago
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inn [45]

Answer:

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Explanation:

Given :

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This is unclear. What are the objects? Is it a balloon? A rubber ball?
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3 years ago
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