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oee [108]
3 years ago
12

Determine the centripetal force on a vehicle rounding a circular curve with a radius of 80 m at a constant speed of 90 km/h if t

he vehicle's mass is 2,000 kg. (Hint: First express the velocity in meters per second)
Physics
1 answer:
quester [9]3 years ago
3 0
Mass of the vehicle = 2000 kg
Velocity of the vehicle = 90 km/hr
                                   = 25 m/s
Radius of the curve = 80 m
Then
Centripetal force = [2000 * (25)^2]/80
                            = (2000 * 625)/80
                            = 15625 kg m/s
                            = 15625 Newton second
I hope that this is the answer that you were looking for and the answer has come to your desired help. 
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7 0
3 years ago
Calculate the hydrostatic difference in blood pressure between the brain and the foot in a person of height 1.93 m. The density
Slav-nsk [51]

Answer:

Explanation:

Given: Density of blood = 1.03 × 10³ Kg/m³, Height =  1.93 m g = 9.8 m/s²

pressure at the brain is equal to atmospheric pressure. = Hydro-static

pressure(ρ₀)

∴ pressure of the foot = pressure of the brain(ρ₀) + ( density of blood × acceleration due to gravity × height)(ρgh)

Hydro-static pressure = pressure at the feet- pressure at the brain(ρ₀)

Hydro-static pressure (Δp) = (ρgh + ρ₀) - ρ₀ = ρgh

Hydro-static pressure = 1.03 × 10³ × 9.8 × 1.93 = 1.948 × 10⁴ Pa

∴  Hydro-static pressure ≈ 1.95 × 10⁴ Pa

3 0
2 years ago
Which process binds together sediment to form new rock?
vekshin1

Answer:

its cementation i got it correct

Explanation:

6 0
3 years ago
Two electric charges are moved so that they are twice as far apart as they had originally been. Is the force they experience fro
Natasha_Volkova [10]

Answer:

No.

Explanation:

The force that two particle experience is inversely proportional to the sqare of the distance, this is:

F \  \alpha \  \frac{1}{D^{2}} for a distance D

If we move them so that D is doubled:

\frac{1}{2^{2}.D^{2}  }= \frac{1}{4} \eq  \frac{1}{.D^{2}  } \eq

Then the force they experience is one fourth of the original.

5 0
3 years ago
A 3.6-volt battery is used to operate a cell phone
Marina CMI [18]

Explanation :

It is given that,

Potential energy, V=3.6\ V

Power dissipated,  P=0.064\ Watt

We know that the power dissipated is given by :

P=VI

I is the current passing through the phone.

I=\dfrac{P}{V}

I=\dfrac{0.064\ W}{3.6\ V}

I=0.017\ A

or

I = 0.018 A

Hence, the current that passes through the phone is (1) 0.018 A.

3 0
3 years ago
Read 2 more answers
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