Answer:
The velocity of the hay bale is - 0.5 ft/s and the acceleration is 
Solution:
As per the question:
Constant velocity of the horse in the horizontal, 
Distance of the horse on the horizontal axis, x = 10 ft
Vertical distance, y = 20 ft
Now,
Apply Pythagoras theorem to find the length:


Now,
(1)
Differentiating equation (1) w.r.t 't':


where
= Rate of change of displacement along the horizontal
= Rate of change of displacement along the vertical
= velocity along the x-axis.
= velocity along the y-axis



Acceleration of the hay bale is given by the kinematic equation:





Answer: option D) 42.4 N
The weight of the frame is balanced by the vertical component of tension.
W = T sin θ + T sin θ = 2 T sin θ
The tension in each cable is T = 30 N
Angle made by the cables with the horizontal, θ = 45°
⇒ W = 2×30 N × sin 45° = 2 × 30 N × 0.707 = 42.4 N
Hence, the weight of the frame is 42.4 N. Correct option is D.
Answer:
The minimum speed is 14.53 m/s.
Explanation:
Given that,
r = 11 m
Friction coefficient = 0.51
Suppose we need to find the minimum speed, that the cylinder must make a person move at to ensure they will stick to the wall
When frictional force becomes equal to or greater than the weight of person
Then, he sticks to the wall
We need to calculate the minimum speed
Using formula for speed

Where,


Put the value into the formula


Hence, The minimum speed is 14.53 m/s.
Answer:
Constructive interference
Explanation:
Here, the medium is same, same wavelength, same frequency, same amplitude and same direction of propagation.
Let the intensity of waves be I which is same for both
The formula for the net intensity is

where, Ф be the phase difference
So, 
Here, IR is maximum so the interference is constructive in nature.
Answer:
The frequency of the photon is
.
Explanation:
Given that,
Energy
We need to calculate the energy
Using relation of energy

Where,
= energy spacing


Put the value of h into the formula


Hence, The frequency of the photon is
.