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3 years ago

Which equation could not be used to determine straight line acceration?

Physics

1 answer:

uranmaximum [27]3 years ago

5 0

Answer:

the answer for the question is the last option

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When a basketball player jumps to make a shot, once the feet are off

In-s [12.5K]

There's no question.I think these are just the answer choices

3 0

3 years ago

A heavy stone of mass m is hung from the ceiling by a thin 8.25-g wire that is 65.0 cm long. When you gently pluck the upper end

Dominik [7]

Answer:

wavelength = 0.8989 m

Explanation:

Given data:

weight of wire is 8.25 g

length of wire is 65 cm

speed of sound in room is 344 m/s

time of returning of pulse is 7.84 ms

There are three time period

Time period $= \frac{7.84\times 10^{-3}}{3} = 2.6133\times 10^{-3} s$

$frequency = \frac{1}{T}$

$=\frac{ 1}{2.6133\times 10^{-3})} = 382.6579 Hz$

velocity = wavelength × frequency

wavelength $= \frac{velocity}{frequency}$

$= \frac{344}{382.6579}$

wavelength = 0.8989 m

6 0

3 years ago

Two teams of nine members each engage in a tug of war. Each of the first team’s members has an average mass of 65 kg and exerts

Leviafan [203]

Answer:

.team 1 a = 20.8 m/s² team 2 a = 19.2 m/s²

Explanation:

Let's use Newton's second law to calculate the acceleration of the two groups

F = ma

a = F / M

Group 1

a = 9 1354/9 65

a = 20.8 m / s²

Group 2

a = 9 1364/9 71

a = 19.2 m / s²

If the two groups pull against each other, group 1 should win, by creating a greater acceleration.

Δa = 20.8 -19.2

Δa = 1.6 m / s²

4 0

4 years ago

Which of newtons laws explains why your hands get red when you press them hard against a wall

Andrei [34K]

Most likely Newton's 3rd law.

3 0

3 years ago

A thin film of oil of thickness t is floating on water. The oil has index of refraction no = 1.4. There is air above the oil. Wh

vesna_86 [32]

Answer:t=0.1205

Explanation:

Given

Refractive index of oil $\left ( \mu \right )=1.4$

Wavelength of red light =675 mm

Condition for constructive interference is

$2\mu _{oil}t=\frac{m\lambda }{2}$

$t=\frac{m\lambda }{4\mu _{oil}}$

For m= 1 i.e. for minimum thickness

$t=\frac{1\times 675\times 10^{-9}}{4\times 1.4}$

$t=0.1205 \mu m$

5 0

3 years ago