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3 years ago

Which of the following is a situation in which you need to know the slope?

Mathematics

1 answer:

lorasvet [3.4K]3 years ago

5 0

I would say the constructing a wheel chair ramp one

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Great Granola makes a trail mix consisting of peanuts, cashews, raisins, and dried cranberries. The trail mix sells for $3.50, a

Leno4ka [110]

Answer:

the answer is the average amount of cashews per bag to determine average cost

the amount of variation in ounces of cashews in the bags of trail mix

which factory produces the most consistent ounces of cashews in each bags of trail mix

Step-by-step explanation:

5 0

3 years ago

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The graph of a linear relationship is shown below. Does this graph show a proportional relationship?

Leona [35]

Yes it does because the line is straight.

3 0

3 years ago

A ball is thrown into the air from an apartment balcony and falls to the ground. The height of the ball, h metres, t seconds aft

andriy [413]

Answer:

$1+2\sqrt{2}$ seconds

Step-by-step explanation:

When the ball hits the ground, its height will obviously be 0. Therefore, you can set up the equation the following way:

$0=-5t^2+10t+35 \\\\-5(t^2-2t-7)=0$

Plugging this into the quadratic equation, you get:

$t=\dfrac{2\pm\sqrt{4+28}}{2}= \\\\\dfrac{2\pm4\sqrt{2}}{2}= \\\\1\pm2\sqrt{2}$

Since the time must be positive, it takes the ball $1+2\sqrt{2}$ seconds to hit the ground, or around 3.828. Hope this helps!

7 0

2 years ago

Ok I’m actually dumb lol help me please.

mezya [45]

Answer:

x =20

Step-by-step explanation:

As a line is 180 degrees

So 7x + 40 would be 180, which would lead us with the equation:

7x+40=180

=7x =140 (minus both sides by 40)

=x =20 (divide both sides by 7)

3 0

3 years ago

Can someone please explain this to me? Thanks!

Makovka662 [10]

Answer: Choice D

$\displaystyle F\ '(x) = 2x\sqrt{1+x^6}\\\\$

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Explanation:

Let g(t) be the antiderivative of $g'(t) = \sqrt{1+t^3}$ . We don't need to find out what g(t) is exactly.

Recall by the fundamental theorem of calculus, we can say the following:

$\displaystyle \int_{a}^{b} g'(t)dt = g(b)-g(a)$

This theorem ties together the concepts of integrals and derivatives to show that they are basically inverse operations (more or less).

So,

$\displaystyle F(x) = \int_{\pi}^{x^2}\sqrt{1+t^3}dt\\\\ \displaystyle F(x) = \int_{\pi}^{x^2}g'(t)dt\\\\ \displaystyle F(x) = g(x^2) - g(\pi)\\\\$

From here, we apply the derivative with respect to x to both sides. Note that the $g(\pi)$ portion is a constant, so $g'(\pi) = 0$

$\displaystyle F(x) = g(x^2) - g(\pi)\\\\ \displaystyle F \ '(x) = \frac{d}{dx}[g(x^2)-g(\pi)]\\\\\displaystyle F\ '(x) = \frac{d}{dx}[g(x^2)] - \frac{d}{dx}[g(\pi)]\\\\ \displaystyle F\ '(x) = \frac{d}{dx}[x^2]*g'(x^2) - g'(\pi) \ \text{ .... chain rule}\\\\$

$\displaystyle F\ '(x) = 2x*g'(x^2) - 0\\\\ \displaystyle F\ '(x) = 2x*g'(x^2)\\\\ \displaystyle F\ '(x) = 2x\sqrt{1+(x^2)^3}\\\\ \displaystyle F\ '(x) = \boldsymbol{2x\sqrt{1+x^6}}\\\\$

Answer is choice D

5 0

2 years ago

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