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nevsk [136]
3 years ago
7

Find the difference between the medians of Set A and Set B as a multiple of the interquartile range of Set A. A) 1 2 B) 3 4 C) 1

1 2 D) 2
Mathematics
2 answers:
inysia [295]3 years ago
8 0

Answer:

B) 3/4

Step-by-step explanation:

3 /4

Set A interquartile range = 4

Difference between medians is 3.

Therefore,  3 /4

dimaraw [331]3 years ago
3 0

Answer:

b

Step-by-step explanation:

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dexar [7]

Peter reflecting trapezoid ABCD across the y-axis would not change the degree measurement of angle A

The degree measurement of angle A is 115 degrees

<h3>How to determine the degree measurement of angle A?</h3>

From the question, we have:

A = 115 degrees

B = 65 degrees

The transformation is a reflection across the y-axis

Reflection is a rigid transformation; and it does not change the angle measure or side lengths.

After the transformation; we have:

A = 115 degrees

B = 65 degrees

Hence, the degree measurement of angle A is 115 degrees

Read more about transformation at:

brainly.com/question/4289712

8 0
2 years ago
Given a vertical asymptote at x=0 and a horizontal asymptote at y=2, which values of x should be used to determine coordinate?
vodka [1.7K]

The y and a coordinated go left

5 0
3 years ago
PLEASE HELP.
pentagon [3]

Let x represent the number of shirts. Let y represent the number of pens.

If shirts are on sale for $11.99 each, then x shirts cost $11.99x.

If pants are on sale for $12.99 each, then y pants cost $12.99y.

The total cost is $(11.99x+12.99y).

Sarah can spend up to $65. Then an inequality that represents this situation is

11.99x+12.99y≤65 (this inequality holds when Sarah can spend $65 too)

or

11.99x+12.99y<65 (this inequality holds when Sarah can spend less than $65).

3 0
3 years ago
A store pays a manufacturer $20 for a hat. To make a profit, the store prices the hat 60% higher than the amount they paid. Late
Molodets [167]

Answer:

The clearance price is $17.28.

The clearance price will not give the store any profit.

Step-by-step explanation:

We have been given that a store pays a manufacturer $20 for a hat. To make a profit, the store prices the hat 60% higher than the amount they paid.

The price of the hat after increasing the price by 60% will be:

\text{Price of the hat after an increase of 60\%}=20+(\frac{60}{100}*20)

\text{Price of the hat after an increase of 60\%}=20+(0.60*20)

\text{Price of the hat after an increase of 60\%}=20+12

\text{Price of the hat after an increase of 60\%}=32

So, the price of hat after the increase of 60% will be $32.

As the sale reduces the price of hat by 10%, so the price of hat after sale will be:

\text{Price of the hat after sale of 10\%}=32-(\frac{10}{100}*32)

\text{Price of the hat after sale of 10\%}=32-(0.10*32)

\text{Price of the hat after sale of 10\%}=32-3.2

\text{Price of the hat after sale of 10\%}=28.8

So the price of hat after 10% sale will be $28.8.

As the clearance sale reduces the price by 40%, so price of hat after clearance sale will be 28.8 minus 40% of 28.8.

\text{Price of the hat after clearance sale}=28.8-(\frac{40}{100}*28.8)

\text{Price of the hat after clearance sale}=28.8-(0.40*28.8)

\text{Price of the hat after clearance sale}=28.8-11.52

\text{Price of the hat after clearance sale}=17.28

Therefore, the clearance price is $17.28.

As store has purchased the hat from manufacturer for $20 and sold it $17.28, therefore, the store will not have a profit.

7 0
3 years ago
Simplify the expression below and write it as a single logarithm:
OLEGan [10]

The simplification of 3log(x + 4) – 2log(x – 7) + 5log(x - 2) - log(x^2) is \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)

<u>Solution:</u>

Given, expression is 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)

We have to write in as single logarithm by simplifying it.

Now, take the given expression.

\rightarrow 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)

Rearranging the terms we get,

\left.\rightarrow 3 \log (x+4)+5 \log (x-2)-2 \log (x-7)+\log \left(x^{2}\right)\right)

\text { since a } \times \log b=\log \left(b^{a}\right)

\rightarrow \log (x+4)^{3}+\log (x-2)^{5}-\left(\log (x-7)^{2}+\log \left(x^{2}\right)\right)

\text { We know that } \log a \times \log b=\log a b

\rightarrow \log \left((x+4)^{3} \times(x-2)^{5}\right)-\left(\log \left((x-7)^{2} \times\left(x^{2}\right)\right)\right.

\text { We know that } \log a-\log b=\log \frac{a}{b}

\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)

Hence, the simplified form \rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)

4 0
3 years ago
Read 2 more answers
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