Complete Question
A 0.025-kg block on a horizontal frictionless surface is attached to an ideal massless spring whose spring constant is 150 N/m. The block is pulled from its equilibrium position at x = 0.00 m to a displacement x = +0.080 m and is released from rest. The block then executes simple harmonic motion along the horizontal x-axis. When the displacement is x = 0.024 m, what is the kinetic energy of the block?
Answer:
The kinetic energy is ![KE = 0.4368\ J](https://tex.z-dn.net/?f=KE%20%3D%200.4368%5C%20%20J)
Explanation:
From the question we are told that
The mass of the block is ![m= 0.025\ kg](https://tex.z-dn.net/?f=m%3D%200.025%5C%20kg)
The spring constant is ![k = 150 N/m](https://tex.z-dn.net/?f=k%20%3D%20150%20N%2Fm)
The length of first displacement is ![x_1 = 0.80 \ m](https://tex.z-dn.net/?f=x_1%20%3D%200.80%20%5C%20m)
The length of first displacement is ![x_2 = 0.024 \ m](https://tex.z-dn.net/?f=x_2%20%3D%200.024%20%5C%20m)
At the
the kinetic energy is mathematically evaluated as
![KE = \Delta E](https://tex.z-dn.net/?f=KE%20%20%3D%20%5CDelta%20E)
Where
is the change in energy stored on the spring which is mathematically represented as
![\Delta E = \frac{1}{2} k (x_1 ^2 - x_2^2)](https://tex.z-dn.net/?f=%5CDelta%20E%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20k%20%28x_1%20%5E2%20-%20x_2%5E2%29)
=> ![KE = \frac{1}{2} k (x_1 ^2 - x_2^2)](https://tex.z-dn.net/?f=KE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20k%20%28x_1%20%5E2%20-%20x_2%5E2%29)
Substituting value
![KE = \frac{1}{2} * 150 * (0.08^2 - 0.024^2)](https://tex.z-dn.net/?f=KE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2A%20150%20%2A%20%20%280.08%5E2%20-%200.024%5E2%29)
![KE = 0.4368\ J](https://tex.z-dn.net/?f=KE%20%3D%200.4368%5C%20%20J)
Freezing since the molecules are coming closer togther
ANSWER: (ROLE of Producers in the cycle:totake in carbon dioxide from the atmosphere during photosynthesis and release carbon dioxide during respiration,ROLE of Consumers:to contribute to the carbon cycle when they perform respiration and expel carbon dioxide into the atmosphere)
Hope this Helps SOMEONE!!
,Thank you
Answer:
![F_g = 8.9 \times 10^{-30} N](https://tex.z-dn.net/?f=F_g%20%3D%208.9%20%5Ctimes%2010%5E%7B-30%7D%20N)
![F_e = 1.6 \times 10^{-17} N](https://tex.z-dn.net/?f=F_e%20%3D%201.6%20%5Ctimes%2010%5E%7B-17%7D%20N)
![F_m = 4.72 \times 10^{-17} N](https://tex.z-dn.net/?f=F_m%20%3D%204.72%20%5Ctimes%2010%5E%7B-17%7D%20N)
Explanation:
For gravitational force we know that
F = mg
now we have
![m = 9.1 \times 10^{-31} kg](https://tex.z-dn.net/?f=m%20%3D%209.1%20%5Ctimes%2010%5E%7B-31%7D%20kg)
![F_g = (9.1 \times 10^{-31})(9.8)](https://tex.z-dn.net/?f=F_g%20%3D%20%289.1%20%5Ctimes%2010%5E%7B-31%7D%29%289.8%29)
![F_g = 8.9 \times 10^{-30} N](https://tex.z-dn.net/?f=F_g%20%3D%208.9%20%5Ctimes%2010%5E%7B-30%7D%20N)
Now electrostatic force
![F = qE](https://tex.z-dn.net/?f=F%20%3D%20qE)
here we have
![F = (1.6 \times 10^{-19})(100)](https://tex.z-dn.net/?f=F%20%3D%20%281.6%20%5Ctimes%2010%5E%7B-19%7D%29%28100%29)
![F = 1.6 \times 10^{-17} N](https://tex.z-dn.net/?f=F%20%3D%201.6%20%5Ctimes%2010%5E%7B-17%7D%20N)
Now magnetic force on it is given by
![F_{m} = qvB](https://tex.z-dn.net/?f=F_%7Bm%7D%20%3D%20qvB)
![F_m = (1.6 \times 10^{-19})(5.90 \times 10^6)(50 \times 10^{-6})](https://tex.z-dn.net/?f=F_m%20%3D%20%281.6%20%5Ctimes%2010%5E%7B-19%7D%29%285.90%20%5Ctimes%2010%5E6%29%2850%20%5Ctimes%2010%5E%7B-6%7D%29)
![F_m = 4.72 \times 10^{-17} N](https://tex.z-dn.net/?f=F_m%20%3D%204.72%20%5Ctimes%2010%5E%7B-17%7D%20N)
Answer:
It's red
Explanation:
Blue light has a shorter distance between wave crests than orange light. Red light has a longer distance between wave crests than blue light.