1. A car is slowing down at a constant rate from 40 m/s to come to a stop. The acceleration is - 5 m/s2. How
1 answer:
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Answer:
10.09 N
Explanation:
Analogously to Newton's second law, torque can be defined as:
Here, I is the moment of inertia and is the angular acceleration. We have:
Torque is the vector product of the position vector of the point at which the force is applied by the force vector:
Since the effective lever arm is perpendicular to the force, the angle between them is . The magnitud of this vector product is defined as:
.
Solving for F and replacing the known values:
Answer:
(a). The time is 26.67 sec.
(b). The distance traveled during this period is 1066.9 m.
Explanation:
Given that,
Speed = 80 m/s
Acceleration = 3 m/s
Initial velocity = 0
(a). We need to calculate the time
Using equation of motion
Put the value into the formula
The time is 26.67 sec.
(b). We need to calculate the distance traveled during this period
Using equation of motion
The distance traveled during this period is 1066.9 m.
Hence, This is the required solution.