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2 years ago

How are feathers heavy as steel?

1 answer:

6 0

Answer: This is because they both weigh a pound. As the density of steel is much greater than the density of feathers, a pound of feathers would make up a much greater volume.

Explanation: brainliest plz :)

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. One long wire carries a current of 30 A along the entire x axis. A second-long wire carries a current of 40 A perpendicular to

d1i1m1o1n [39]

Answer:

magnitude of net magnetic field at given point is

$B = 5 \times 10^{-6} T$

Explanation:

As we know that magnetic field due to a long current carrying wire is given as

$B = \frac{\mu_o i}{2\pi r}$

here we we will find the magnetic field due to wire which is along x axis is given as

$i = 30 A$

r = 2 m

now we have

$B_1 = \frac{4\pi \times 10^{-7} (30)}{2\pi (2m)}$

$B_1 = 3\times 10^{-6} T$ into the plane

Now similarly magnetic field due to another wire which is perpendicular to xy plane is given as

$i = 40 A$

r = 2 m

now we have

$B_2 = \frac{4\pi \times 10^{-7} (40)}{2\pi (2m)}$

$B_2 = 4\times 10^{-6} T$ along + x direction

Since the two magnetic field is perpendicular to each other

So here net magnetic field is given as

$B = \sqrt{B_1^2 + B_2^2}$

$B = 5 \times 10^{-6} T$

5 0

3 years ago

Which is an example of natural erosion? ice forming in cracks of rocks acid rain falling on sidewalks waves washing over rocks o

oee [108]

Ice forming in cracks of rocks

5 0

3 years ago

Read 2 more answers

Adaptive organ of duck

postnew [5]

Answer:

brain

Explanation:

6 0

2 years ago

You weigh 730N. What would you weigh if the earth were six times as massive as it is and its radius were four times its present

Ber [7]

The new weight is 273.8 N

Explanation:

The weight of an object on Earth is given by

$W=mg$

where

m is the mass of the object

g is the acceleration of gravity

The acceleration of gravity at the Earth's surface can be rewritten as

$g=\frac{GM}{R^2}$

where

G is the gravitational constant

M is the Earth's mass

R is the Earth's radius

Substituting into the previous equation,

$W=\frac{GMm}{R^2}$

We said that in normal conditions, the weight of the person is 730 N:

$W=\frac{GMm}{R^2}=730 N$

Later, we are said that:

The mass of the Earth increases by a factor of 6, $M'=6M$
The radius of the Earth increases by a factor of 4, $R'=4R$

Substituting into the equation, we find the new weight of the person in these conditions:

$W'=\frac{G(6M)m}{(4R)^2}=\frac{6}{16}(\frac{GMm}{R^2})=\frac{3}{8}W$

So, the new weight is 3/8 of the original weight, therefore:

$W'=\frac{3}{8}(730)=273.8 N$

Learn more about gravity:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

3 0

2 years ago

How do I find the velocity of a moving object?

Aliun [14]

If you know the distance and the time I travelled that distance.

You just have to divide the time from the distance to get velocity

V =d
_

t

8 0

3 years ago