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PtichkaEL [24]
3 years ago
10

The figure below shows two forces F1 = 30.0 N and F2 = 20.0 N acting on an object that

Physics
1 answer:
Viefleur [7K]3 years ago
4 0

Answer:

0.2Nm

Explanation:

F1 = 30.0N

F2 = 20.0N

R = 2.0cm = 0.02m

F1R1 - F2R2 = net Torque

30(0.02) - 20(0.02) = net Torque

0.6-0.4 = net Torque

Therefore net Torque = 0.2Nm

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If the radius of an object in circular motion is doubled, what change will occur in the centripetal force?
cestrela7 [59]

Answer:

The centripetal force will be 1/2 as big as it was. (option c)

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So if we start with such formula with a given mass, radius, and tangential velocity, and then we move to a situation where everything stays the same except for the radius which doubles, then the new centripetal force (F'_c) will be given by: F'_c=m\,* \frac{v^2}{2r}

and this is half (1/2) of the original force:

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3 years ago
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A 900-kg car traveling east at 15.0 m/s collides with a 750-kg car traveling north at 20.0 m/s. The cars stick together. What is
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Answer:

12.2 m/s

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