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Westkost [7]
3 years ago
7

The Perry Company reported Accounts Receivable, Net of $65,800 at the beginning of the year and $73,000 at the end of the year.

If the company's net sales revenue during the fourth year was $884,000, what are the days to collect during year? (Round all calculations to 1 decimal place.)
Business
1 answer:
VikaD [51]3 years ago
4 0

Answer:

28.6 days

Explanation:

Avg Receivables= Beg Receivables + Ending Receivables /2

=65,800+73,000/2

=$138,800/2

=$69,400

Receivable turn over= Net Sales/ Avg Receivables

=884,000/69,400

=12.74

days to collect during year= 365/ Receivable turn over =365/12.7

=28.6 days

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Variable costs for Coronado Industries are 30% of sales. Its selling price is $120 per unit. If Coronado sells one unit more tha
nika2105 [10]

Answer:

Income will increase by $84.

Explanation:

<u>The break-even point is the number of units required to cover the fixed costs. Net income is zero.</u>

First, we need to calculate the unitary variable cost:

Unitary variable cost= 120*0.3= $36

<u>Now, the unitary contribution margin:</u>

unitary contribution margin= 120 - 36

unitary contribution margin= $84

Income will increase by $84.

8 0
2 years ago
Suppose that the S&amp;P 500, with a beta of 1.0, has an expected return of 13% and T-bills provide a risk-free return of 4%. a.
Aleksandr [31]

Answer:

a. The answers are as follows:

(i) Expected of Return of Portfolio = 4%; and Beta of Portfolio = 0

(ii) Expected of Return of Portfolio = 6.25%; and Beta of Portfolio = 0.25

(iii) Expected of Return of Portfolio = 8.50%; and Beta of Portfolio = 0.50

(iv) Expected of Return of Portfolio = 10.75%; and Beta of Portfolio = 0.75

(v) Expected of Return of Portfolio = 13%; and Beta of Portfolio = 1.0

b. Change in expected return = 9% increase

Explanation:

Note: This question is not complete as part b of it is omitted. The complete question is therefore provided before answering the question as follows:

Suppose that the S&P 500, with a beta of 1.0, has an expected return of 13% and T-bills provide a risk-free return of 4%.

a. What would be the expected return and beta of portfolios constructed from these two assets with weights in the S&P 500 of (i) 0; (ii) 0.25; (iii) 0.50; (iv) 0.75; (v) 1.0

b. How does expected return vary with beta? (Do not round intermediate calculations.)

The explanation to the answers are now provided as follows:

a. What would be the expected return and beta of portfolios constructed from these two assets with weights in the S&P 500 of (i) 0; (ii) 0.25; (iii) 0.50; (iv) 0.75; (v) 1.0

To calculate these, we use the following formula:

Expected of Return of Portfolio = (WS&P * RS&P) + (WT * RT) ………… (1)

Beta of Portfolio = (WS&P * BS&P) + (WT * BT) ………………..………………. (2)

Where;

WS&P = Weight of S&P = (1) – (1v)

RS&P = Return of S&P = 13%, or 0.13

WT = Weight of T-bills = 1 – WS&P

RT = Return of T-bills = 4%, or 0.04

BS&P = 1.0

BT = 0

After substituting the values into equation (1) & (2), we therefore have:

(i) Expected return and beta of portfolios with weights in the S&P 500 of 0 (i.e. WS&P = 0)

Using equation (1), we have:

Expected of Return of Portfolio = (0 * 0.13) + ((1 - 0) * 0.04) = 0.04, or 4%

Using equation (2), we have:

Beta of Portfolio = (0 * 1.0) + ((1 - 0) * 0) = 0

(ii) Expected return and beta of portfolios with weights in the S&P 500 of 0.25 (i.e. WS&P = 0.25)

Using equation (1), we have:

Expected of Return of Portfolio = (0.25 * 0.13) + ((1 - 0.25) * 0.04) = 0.0625, or 6.25%

Using equation (2), we have:

Beta of Portfolio = (0.25 * 1.0) + ((1 - 0.25) * 0) = 0.25

(iii) Expected return and beta of portfolios with weights in the S&P 500 of 0.50 (i.e. WS&P = 0.50)

Using equation (1), we have:

Expected of Return of Portfolio = (0.50 * 0.13) + ((1 - 0.50) * 0.04) = 0.0850, or 8.50%

Using equation (2), we have:

Beta of Portfolio = (0.50 * 1.0) + ((1 - 0.50) * 0) = 0.50

(iv) Expected return and beta of portfolios with weights in the S&P 500 of 0.75 (i.e. WS&P = 0.75)

Using equation (1), we have:

Expected of Return of Portfolio = (0.75 * 0.13) + ((1 - 0.75) * 0.04) = 0.1075, or 10.75%

Using equation (2), we have:

Beta of Portfolio = (0.75 * 1.0) + ((1 - 0.75) * 0) = 0.75

(v) Expected return and beta of portfolios with weights in the S&P 500 of 1.0 (i.e. WS&P = 1.0)

Using equation (1), we have:

Expected of Return of Portfolio = (1.0 * 0.13) + ((1 – 1.0) * 0.04) = 0.13, or 13%

Using equation (2), we have:

Beta of Portfolio = (1.0 * 1.0) + (1 – 1.0) * 0) = 1.0

b. How does expected return vary with beta? (Do not round intermediate calculations.)

There expected return will increase by the percentage of the difference between Expected Return and Risk free rate. That is;

Change in expected return = Expected Return - Risk free rate = 13% - 4% = 9% increase

4 0
2 years ago
An investor originally paid $22,000 for a vacant lot twelve years ago. If the investor is able to sell the lot today for $62,000
MArishka [77]

Answer:

b.9%

Explanation:

Formula for annual rate of return formula is as follows;

Annual rate of return = [ (New value/ Initial value)^(1/t) ] -1

t = the total holding period of investment = 12 years

Old value = 22,000

New value = 62,000

Next, plug in the numbers to the formula;

Annual rate of return; r = [ (62,000/22,000) ^(1/12) ] -1

r = [2.8182 ^(1/12)] - 1

r = 1.0902 -1

r = 0.0902 or 9%

4 0
3 years ago
Match the vocabulary word to the correct definition.
maria [59]
I’m just thinking it is c
8 0
3 years ago
A storm on one of the planets listed in the table lasted for 132 hours, or 5.5 of the planet's days. The equation 5.5h = 132 giv
padilas [110]

Answer:

<u><em></em></u>

  • <u><em>The planet is Earth</em></u>

Explanation:

<em>1. Equation (given)</em>:

  • 5.5h = 132

2. Solve by applying division property of equalities: divide both sides by 5.5

  • h = 132/5.5
  • h = 24.0

The equation gives the length in hours of a day, then the solution h = 24.0 means that the length of the day on the planet is 24.0 horas.

The table is:

Length of Day

Planet           Length of Day (hours)

Earth                   24.0

Mars                    24.7

Jupiter                  9.9

Therefore, the solution h = 24.0 shows that the planet is Earth.

5 0
3 years ago
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