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Korolek [52]
3 years ago
10

80 % of _ games is 32 games

Mathematics
2 answers:
ddd [48]3 years ago
8 0
40 games is the answer you're looking for
andrew-mc [135]3 years ago
7 0
80% × x = 32
.80x = 32
x = 32/.8
x = 40
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Given T5 = 96 and T8 = 768 of a geometric progression. Find the first term,a and the common ratio,r.
Alona [7]

Answer:

Of the given geometric sequence, the first term a is 6 and its common ratio r is 2.

Step-by-step explanation:

Recall that the direct formula of a geometric sequence is given by:

\displaystyle T_ n = ar^{n-1}

Where <em>T</em>ₙ<em> </em>is the <em>n</em>th term, <em>a</em> is the initial term, and <em>r</em> is the common ratio.

We are given that the fifth term <em>T</em>₅ = 96 and the eighth term <em>T</em>₈ = 768. In other words:

\displaystyle T_5 = a r^{(5) - 1} \text{ and } T_8 = ar^{(8)-1}

Substitute and simplify:

\displaystyle 96 = ar^4 \text{ and } 768 = ar^7

We can rewrite the second equation as:

\displaystyle 768 = (ar^4) \cdot r^3

Substitute:

\displaystyle 768 = (96) r^3

Hence:

\displaystyle r = \sqrt[3]{\frac{768}{96}} = \sqrt[3]{8} = 2

So, the common ratio <em>r</em> is two.

Using the first equation, we can solve for the initial term:

\displaystyle \begin{aligned} 96 &= ar^4 \\ ar^4 &= 96 \\ a(2)^4 &= 96 \\ 16a &= 96 \\ a &= 6 \end{aligned}

In conclusion, of the given geometric sequence, the first term <em>a</em> is 6 and its common ratio <em>r</em> is 2.

7 0
2 years ago
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