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Naily [24]
3 years ago
9

A total of 503 tickets were sold for the school play they were either adult tickets or student tickets there were 53 more studen

t tickets sold than the adult tickets how many adult tickets were sold
Mathematics
1 answer:
makvit [3.9K]3 years ago
7 0
The adult tickets sold: 198.5
The student tickets sold:304.5
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Determine the mean absolute<br> deviation 8, 0, 4, 7, 4, 5, 3, 3
velikii [3]

Answer:

I would say it's 4 or 7.

Step-by-step explanation:

its wrong i just know it is :(

5 0
2 years ago
Which system is equivalent to<br> y= 9x^2<br> x+y=5<br> ?
melomori [17]

Answer : Option A

Explanation:

we can clearly see that from x+ y=5 we can substitute  y = 5-x in y = 9x^2

Option B is clearly incorrect  x can not be y -5

Option C  is incorrect because y can not be 5 +x

Option D is incorrect because  its y = 9x^2 not y^2 =9x^2 so y can not be 3x

if its y^2 = 9x^2 then  only  implies y =  3x

7 0
3 years ago
Read 2 more answers
Summer is having a pool party at her house In the ice chest me are of lemonade and 13 bottles of water If she randomly grabs abo
zlopas [31]
Probability  = 

       (number of ways it can come out the way you want it to)
divided by
       (total number of ways it can come out).

Total number of ways it can come out =

                    number of bottles in the cooler

                 = (10 + 15 + 13) = 38 .

Number of ways it can come out the way you want it to =

                   (soda + lemonade)

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Probability of coming out the way you want it to =

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7 0
3 years ago
This is one correct way to subtract 3.98 from 11.35. What is another correct way?
krok68 [10]
In decimal form=-7.37
In fraction form plzz refer to the attachment
8 0
3 years ago
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A card is drawn from a pack of 52 cards. Find the probability of drawing an ace given that it is diamond.4/521/132/134/13
ICE Princess25 [194]

Solution:

The probability of an event is expressed as

P(event)=\frac{number\text{ of desired outcome}}{number\text{ of possible outcome}}

In a pack of 52 cards, we have

\begin{gathered} number\text{ of diamonds=13} \\ number\text{ of ace= 1} \end{gathered}

Thus, we have the probability to be evaluated as

P(ace)=\frac{1}{13}

8 0
1 year ago
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