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charle [14.2K]
3 years ago
7

12 subtract 33 4ths

Mathematics
1 answer:
frez [133]3 years ago
8 0

Answer:

3.75 or 15/4

Step-by-step explanation:

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Three sisters have ages that are consecutive odd integers. The sum of the age of the youngest and three times the age of the old
kenny6666 [7]

Answer:

youngest   17  

middle  19

oldest    21

Step-by-step explanation:

Three sisters have ages that are consecutive odd integers

youngest = x

middle = x + 2

oldest = x + 4

--------------------

The sum of the age of the youngest

x

and three times the age of the oldest

+ 3(x + 4)

is five less than five times the middle sister’s age

= 5(x + 2) - 5

-----------------------

x + 3(x + 4) = 5(x + 2) - 5

Distribute

x + 3x + 12 = 5x + 10 - 5

Combine like terms

4x + 12 = 5x - 5

Subtract 4x from both sides

12 = x - 5

Add 5 to both sides

17 = x

youngest   x = 17  

middle     x + 2 = 19

oldest     x + 4 = 21

5 0
3 years ago
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