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goldenfox [79]
3 years ago
11

Any help would be greatly appreciated

Mathematics
1 answer:
Andreas93 [3]3 years ago
3 0

Answer:

\boxed{\df \ \ \ \dfrac{b^7}{3} \ \ \ }

Step-by-step explanation:

\dfrac{9h^2b^8}{27h^2b}=\dfrac{h^{2-2}b^{8-1}}{3}=\dfrac{b^7}{3}

as 27=9*3

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