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dsp73
3 years ago
7

Sue wrote the inequality shown, where b>0.

Mathematics
1 answer:
belka [17]3 years ago
8 0

Answer:

x > bc - db

Step-by-step explanation:

\frac{x}{b}-c>-d is a literal equation, which means all the terms are variables.  Solving for the variable 'x':

\frac{x}{b}-c>d

Add 'c' to both sides:

\frac{x}{b}-c+c>-d+c

simplify and multiply both sides by 'b': b(\frac{x}{b})>(c-d)b

simplify and distribute: x > bc - db

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Given that ​f(x) = x + 4 and ​g(x)​ = x^{2} - x, find ​(f​ + g)(​5), if it exists.
user100 [1]

Answer:

4

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Evaluate x2/y + x2/z for x = 6, y = -4, and z = -2.
8_murik_8 [283]

Answer:

-27

Step-by-step explanation:

6^2=36

36/-4=-9

36/-2=-18

-9+-18=-9-18=-27

7 0
3 years ago
Read 2 more answers
Integrate t sec^2 (2t) dt
Neporo4naja [7]
F = t ⇨ df = dt 
dg = sec² 2t dt ⇨ g = (1/2) tan 2t 
⇔ 
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt 
u = 2t ⇨ du = 2 dt 

As integral of tan u = - ln (cos (u)), you get : 

integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant 
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant 
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer 
8 0
3 years ago
Read 2 more answers
B. The 100th term of 60, 110, 160, ... is (Simplify your answer.) How to do this?​
Advocard [28]

The 1st term is 60.

Add 50 to this to get the 2nd term, 60 + 50 = 110.

Add 50 to that to get the 3rd term, 110 + 50 = 160.

Add 50 to that to get the 4th term, 160 + 50 = 210.

And so on...

Notice that in the 2nd term, we added 1 copy of 50 to the 1st term.

In the 3rd, we ultimately added 2 copies of 50 to the 1st term.

In the 4th, we added 3 50s.

And so on... If the pattern continues, then the <em>n</em>-th term can be obtained by adding (<em>n</em> - 1) copies of 50 to the first term.

So, the 100th term is

60 + (100 - 1) * 50 = 5010

5 0
3 years ago
Two lawn care companies are competing for a landscaping contract. Company A charges a $300 consulting fee plus $7 per square foo
kkurt [141]

The square feet of landscaping will the two companies carry out that enables them to charge the same amount is 30

What is the total of the landscaping contract for each company?

The total cost of the  landscaping contract for each of the two companies is the sum of the fixed consulting fee plus the multiple of variable charge per square foot multiplied by the number of square feet of landscaping

Company A:

Total cost=300+7S

S=square foot

Company B:

Total cost=120+13S

At the point where the square foot are the same they charge the same amount

300+7S=120+13S

300-120=13S-7S

180=6S

S=180/6

S=30 square foot

Find out more about total cost on: brainly.com/question/15686427

#SPJ1

4 0
1 year ago
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