Answer:
-27
Step-by-step explanation:
6^2=36
36/-4=-9
36/-2=-18
-9+-18=-9-18=-27
F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
The 1st term is 60.
Add 50 to this to get the 2nd term, 60 + 50 = 110.
Add 50 to that to get the 3rd term, 110 + 50 = 160.
Add 50 to that to get the 4th term, 160 + 50 = 210.
And so on...
Notice that in the 2nd term, we added 1 copy of 50 to the 1st term.
In the 3rd, we ultimately added 2 copies of 50 to the 1st term.
In the 4th, we added 3 50s.
And so on... If the pattern continues, then the <em>n</em>-th term can be obtained by adding (<em>n</em> - 1) copies of 50 to the first term.
So, the 100th term is
60 + (100 - 1) * 50 = 5010
The square feet of landscaping will the two companies carry out that enables them to charge the same amount is 30
What is the total of the landscaping contract for each company?
The total cost of the landscaping contract for each of the two companies is the sum of the fixed consulting fee plus the multiple of variable charge per square foot multiplied by the number of square feet of landscaping
Company A:
Total cost=300+7S
S=square foot
Company B:
Total cost=120+13S
At the point where the square foot are the same they charge the same amount
300+7S=120+13S
300-120=13S-7S
180=6S
S=180/6
S=30 square foot
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