Adeline needs three new pairs of soccer shorts. They cost $12 each.

Mathematics

1 answer:

stealth61 [152]3 years ago

3 0

Answer:

S= 12x3 or 12x3 = S

Step-by-step explanation:

You might be interested in

Let r(t)=⟨t2,1−t,4t⟩. calculate the derivative of r(t)⋅a(t) at t=5, assuming that a(5)=⟨−4,4,−5⟩ and a′(5)=⟨−5,9,3⟩

erastovalidia [21]

$\mathbf r(t)=\langle t^2,1-t,4t\rangle$
$\implies\mathbf r'(t)=\langle 2t,-1,4\rangle$

$\dfrac{\mathrm d(\mathbf r(t)\cdot\mathbf a(t))}{\mathrm dt}\bigg|_{t=5}=\mathbf r'(5)\cdot\mathbf a(5)+\mathbf r(5)\cdot\mathbf a'(5)$
$=\langle10,-1,4\rangle\cdot\langle-4,4,-5\rangle+\langle25,-4,20\rangle\cdot\langle-5,9,3\rangle$
$=(-40-4-20)+(-125-36+60)$
$=-165$

6 0

4 years ago

If the angle is in standard position and P(x, y) is a point on the terminal side of , and r is the distance from the origin to P

Ghella [55]

Answer:

x^2 + y^2 = r^2

Step-by-step explanation:

See image. "An angle in standard position" means the vertex (point part) of the angle is at the origin (0,0). And one side of the angle is glued onto the x-axis. The other side of the angle is free to rotate around the axis. That's the terminal side. Then there's a point P (x,y) on that side. See image. And r is labelled there. This set up makes a right triangle. So I put Pythagorean theorem as the answer here, but honestly if you are learning any right triangle theorems or trigonometry, you could use this set up. The leg that lays along the x-axis is x units long and the other leg is y units long. The hypotenuse is r units long.

8 0

2 years ago

Describe how the graph of each function differs from the graph of f(x)=|x|. Then determine the domain and range.

Brilliant_brown [7]

A. We can compress the graph of the function $f(x)=|x|$ in the y-direction by multiplying the whole function by a constant C, such that $0$ Since $0$ , the graph of the function $g(x)= 0.6|x|$ is obtained from the graph of the function $f(x)=|x|$ by compression in the y-direction.

B. We can stretch the graph of the function $f(x)=|x|$ in the y-direction by multiplying the whole function by a constant C, such that $C>1.$ Since $4>1,$ , the graph of the function $g(x)= 4|x-3|$ is obtained from the graph of the function $f(x)=|x|$ by compression in the y-direction and translation 3 units to the right.

C. We can flip the graph of the function $f(x)=|x|$ upside down by multiplying the whole function by −1, then translate 1 unit to the left and 5 units up. Then we will get the function $g(x)=-|x+1|+5.$