The probability that a participant successfully catches 3 rainbow trout, given that the participant was a woman is 0.0042.
P(woman) = 12/28
= 3/7
P(men) = 16/28
= 4/7
P(3 trouts) = P(3 trout | women)*P(woman) + P(3 trout | men)*P(man)
= P(3 trout | women)*(3/7) + (15C3 * (0.09^3)*(1-0.09)^(15*3))*(4/7)
= P(3 trout | women)*(3/7) + (0.00476)*(4/7)
P(woman | 3 trout) = P(3 trout | women)*P(woman) / P(3 trouts)
{P(3 trout | women) = p}
p*(3/7) / (p*(3/7) + (0.00476)*(4/7)) = 0.40
p*(3/7)/0.40 = (p*(3/7) + (0.00476)*(4/7))
p*((3/7)/0.40 - (3/7)) = (0.00476)*(4/7)
p = [(0.00476)*(4/7)] / [((3/7)/0.40 - (3/7))]
= 0.0042
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Your answer would be:
The fourth option ---> 12
let's firstly convert the mixed fractions to improper fractions and then subtract, bearing in mind that the LCD of 4 and 2 is 4.
![\bf \stackrel{mixed}{8\frac{3}{4}}\implies \cfrac{8\cdot 4+3}{8}\implies \stackrel{improper}{\cfrac{35}{4}}~\hfill \stackrel{mixed}{7\frac{1}{2}}\implies \cfrac{7\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{15}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{35}{4}-\cfrac{15}{2}\implies \stackrel{\textit{using the LCD of 4}}{\cfrac{(1)35~~-~~(2)15}{4}}\implies \cfrac{35-30}{4}\implies \cfrac{5}{4}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B8%5Cfrac%7B3%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B8%5Ccdot%204%2B3%7D%7B8%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B35%7D%7B4%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B7%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B7%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B15%7D%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B35%7D%7B4%7D-%5Ccfrac%7B15%7D%7B2%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Busing%20the%20LCD%20of%204%7D%7D%7B%5Ccfrac%7B%281%2935~~-~~%282%2915%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B35-30%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B4%7D)
Answer: he collected 22 quarters and 8 fifty-cent pieces
Step-by-step explanation:
Given;
The total amount of money he is to collect is;
A = 20 - 10.50 = $9.50
Let x represent the number of quarter he collected.
Then the number of fifty-cent pieces he collected will be; 30-x
Therefore we can represent it with the equation below;
0.25x + 0.50(30-x) = 9.50
0.25x + 15 - 0.50x = 9.50
0.25x = 15-9.50
x = (15-9.50)/0.25
x = 5.50/0.25
x = 22
The number of fifty-cent is equal to;
30-x = 30-22 = 8
Therefore, he collected 22 quarters and 8 fifty-cent pieces
