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Contact [7]
3 years ago
6

Find the value of a.

Mathematics
2 answers:
Nataly_w [17]3 years ago
6 0
Answer: See below

Explanation:

6a + 11 = 2a + 83
6a - 2a = 83 - 11
4a = 72
a = 72/4
a = 18
Anna [14]3 years ago
6 0
  • Answer:

<em>a = 18°</em>

  • Step-by-step explanation:

<em>we have opposite angles => </em>

<em>=> 6a + 11 = 2a + 83</em>

<em>6a - 2a = 83 - 11</em>

<em>4a = 72</em>

<em>a = 72 : 4</em>

<em>a = 18°</em>

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Three circles can intersect in?
abruzzese [7]

9514 1404 393

Answer:

  (a) two points

Step-by-step explanation:

The curve of a circle can only intersect another circle at a point or in an arc. The intersection will only be an arc if the circles have the same center and radius (are the same circle).

Different circles can only intersect each other at one or two points. Three different circles can intersect in one or two points. The 2-point case is shown in the attachment.

8 0
2 years ago
What are all the solutions to the following<br> equation?<br> |10x + 2| =48
Greeley [361]

\huge \boxed{\mathfrak{Question} \downarrow}

What are all the solutions to the following

equation?

|10x + 2| =48

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

| 10 x + 2 | = 48

Combine like terms and use the properties of equality to get the variable on one side of the equals sign and the numbers on the other side. Remember to follow the order of operations.

|10x+2|=48

Use the definition of absolute value.

10x+2=48  \\ 10x+2=-48

Subtract 2 from both sides of the equation.

10x=46 \\  10x=-50

Divide both sides by 10.

\boxed{ \boxed{ \bf \: x=\frac{23}{5} = 46}} \\    \boxed{\boxed{ \bf \: x=-5 }}

7 0
2 years ago
Read 2 more answers
you are shopping for disposable cameras to hand out at a party. the daytime cameras costs 2.75 dollars and the flash camera cost
LenKa [72]

The solutions that involve whole numbers of cameras are (7, 13), (8, 12), (9, 11), (10, 10), (11, 9), (12, 8) and (13, 7)

<h3>Write and solve a compound inequality for this solution. </h3>

The given parameters are:

  • Daytime cameras = $2.75
  • Flash camera = $4.25
  • Number of cameras = 20 cameras
  • Amount spent = Between $65 and $75

Represent the daytime camera with x and the flash camera with y.

So, we have:

x + y = 20

65 <=2.75x + 4.25y <= 75

Make y the subject in x + y = 20

y = 20 - x

Substitute y = 20 - x in 65 <=2.75x + 4.25y <= 75

65 <=2.75x + 4.25(20 - x) <= 75

Expand

65 <=2.75x + 85 - 4.25x <= 75

This gives

65 <=-1.5x+ 85  <= 75

Subtract 85 from the inequality

-20 <=-1.5x <= -10

Split the inequality

-1.5x >= -20 and -1.5x <= -10

Divide by -1.5

x <= 13.33 and x >= 6.67

Combine the inequality

6.67 <= x <= 13.33

<h3>List all of the solutions that involve whole numbers of cameras.</h3>

In (a), we have:

6.67 <= x <= 13.33

This means that:

x = 7, 8, 9, 10, 11, 12, 13

Recall that:

y = 20 - x

So, we have:

y = 13, 12, 11, 10, 9, 8, 7

So, the solutions that involve whole numbers of cameras are (7, 13), (8, 12), (9, 11), (10, 10), (11, 9), (12, 8) and (13, 7)

Read more about inequality at:

brainly.com/question/25275758

#SPJ1

4 0
2 years ago
The church’s goal for the fundraiser was $18,000. They exceeded their goal by 8%. How much money did they raise?
kifflom [539]

Answer:

19440

Step-by-step explanation:

18000 x 0.08 = 1440

1440 + 18000 = 19440

8 0
3 years ago
99 pts<br><br>rational expressions<br><br>((show your work))<br><br><br>12. (12x^4+9x-10x^2) ÷3x^3
tekilochka [14]

4x + 9 - (10/(3x)) I favored the x^2 then expanded and simplified each rational term

6 0
3 years ago
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