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user100 [1]
4 years ago
6

-7•(-9) need help on this one with full work including

Mathematics
2 answers:
Veseljchak [2.6K]4 years ago
6 0

Answer:

-7×-9

=63

Step-by-step explanation:

If u multiple - with -, I'll get + sign

galina1969 [7]4 years ago
5 0

Answer:

63

Step-by-step explanation:

-7*(-9)

7*9

63

Best of Luck!

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Bev weighs a bag of apples labeled 5 pounds and finds that the weight is actually 72 ounces. To the nearest percent, what is the
Citrus2011 [14]

Answer: 10% is the percentage error.

Step-by-step explanation:

Since, According to the question the labeled weight of the a bag of apples = 5 pounds

Since, 1 pounds = 16 ounces

Therefore the labeled weight of the a bag of apples= 5 × 16 = 80 ounces

But, the actual weight of the bag of apples = 72 ounces

Since, The percentage error = ( experiment value - actual value)×100 /experiment value

Thus, percentage error of the weight of the bag of apple= (80-72)×100/80= 800/80= 10%


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3 years ago
How do you know where to put the decimal point in problem 6?<br><br>6. 4 × 1.18 ​
charle [14.2K]
Decimals are multiplied as if they were whole numbers, and then the decimal point is placed in the product. To find out where the decimal point should be placed, count the number of decimal places after the decimal point in each factor.
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3 years ago
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HELP PLEASE!!! Picture below!
Lady_Fox [76]

Answer:

7 (units)

Step-by-step explanation:

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8 0
3 years ago
PLEASE HELP
Pavel [41]

Answer:

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Step-by-step explanation:

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3 years ago
Find the orthogonal complement W⊥ of W and give a basis for W⊥. W = x y z : x = 1 2 t, y = − 1 2 t, z = 6t.
igor_vitrenko [27]

Answer:

W⊥= (a, b, c)

a = v - (1/2)w

b = v

c = w

Basis for W⊥ = <(1,1,0),(-1/2,0,1)>

Step-by-step explanation:

The orthogonal complement of W is the set of vectors (a,b,c) that satisfy:

(x,y,z)·(a,b,c) = 0

ax + by + cz = 0

So, taking into account that x=12t, y=-12t and z=6t, the equation above is equal to:

12ta + -12tb + 6tc = 0

12a - 12b + 6c = 0

Then, if we made b=v and c=w and solve for a, we get:

12a - 12v + 6w = 0

a = (12v - 6w)/12

a = v - (1/2)w

Therefore, the orthogonal complement W⊥ of W has the form:

W⊥ = (a,b,c) = (v - (1/2)w, v, w)

On the other hand, we can write W⊥ as:

W⊥ = (v - (1/2)w, v, w)

W⊥ = (v,v,0) + ((-1/2)w,0,w)

W⊥ = v(1,1,0) + w(-1/2,0,1)

That means that we can write any vector of W⊥ as a linear combinations of the vectors (1,1,0) and (-1/2,0,1), so they are a basis for W⊥

7 0
3 years ago
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