Answer:
64=2✖️2✖️2✖️2✖️2✖️2
80=2✖️2✖️2✖️2✖️2✖️5
Common factors=2✖️2✖️2✖️2
As HCF= Product of common factors
HCF =2✖️2✖️2✖️2
HCF=16
Step-by-step explanation:
I hope this will help you:)
Answer:
The number of comic books did they have in all = 56
Step-by-step explanation:
The ratio of comics with Susan : Abe = 3 : 5
Let us assume the common factor on this ratio = m
So, the number of comics Susan has = 3 m
The number of comics Abe has = 5 m
Also, given: Abe had 14 more comic books than Susan
So, the number of comics Abe had = 14 + 3 m
⇒ 5 m = 3 m + 14
or, 2 m = 14, or m = 7
So, the number of books Susan has = 3 m = 3 x 7 = 21 books
The number of books Abe has = 5 m = 5 x 7 = 35
So, the book they have in all = 21 + 35 = 56
Answer: <CBE
Step-by-step explanation:
Answer:
True
Step-by-step explanation:
