Dale drove to the mountains last weekend. there was heavy traffic on the way there, and the trip took 7 hours. when dale drove home, there was no traffic and the trip only took 5 hours. if his average rate was 18 miles per hour faster on the trip home, how far away does dale live from the mountains? do not do any rounding.
Answer:
Dale live 315 miles from the mountains
Step-by-step explanation:
Let y be the speed of Dale to the mountains
Time taken by Dale to the mountains=7 hrs
Therefore distance covered by dale to the mountain = speed × time = 7y ......eqn 1
Time taken by Dale back home = 5hours
Since it speed increased by 18 miles per hour back home it speed = y+18
So distance traveled home =speed × time = (y+18)5 ...... eqn 2
Since distance cover is same in both the eqn 1 and eqn 2.
Eqn 1 = eqn 2
7y = (y+18)5
7y = 5y + 90
7y - 5y = 90 (collection like terms)
2y = 90
Y = 45
Substitute for y in eqn 1 to get distance away from mountain
= 7y eqn 1
= 7×45
= 315 miles.
∴ Dale leave 315 miles from the mountains
Answer:
y
Step-by-step explanation:
Associative Property a(bc)=(ab)c
1/4(4y)=(1/4(4))y
y
1 piece of pipe ⇒ 3/4 feet
How many pieces? = 27 feet
27 × 1 ÷ 3/4 = 27 × 4/3 = 36 pieces.
No. You can actually solve this question without doing any math. Her only score that is above a 90 is 93, so it will be brought down lower than a 90 very easily by the 77 and the 82.
19 - (-39) = 19 + 39 = 58
<span>length of a line segment is 58 units.</span>
