C because I
Had this question
Answer:
The correct answer is option (b).
Explanation:
According to the scenario, computation of the given data are as follows:
first we calculate the predetermined OH, then
Predetermined OH rate = Estimated Manufacturing OH Cost ÷ Estimated Direct Labor Hours
= $451,140 ÷ 61,800
= 7.3
So, Applied MOH = 60,500 × 7.3 = $441,650
So, Underapplied OH = Actual MOH - Applied MOH
= $532,000 - $441,650
= $90,350 (under applied)
Answer:
The correct answer is letter "A": be driven to a lower price.
Explanation:
Typically, when there is a producer to producer competition, the competing companies tend to <em>lower </em>their product prices. This happens because of the belief consumers are mainly price driven at the moment of discriminating in choosing to buy one good over another. Though, it allows consumers to at least have a couple of sources from where to choose at a fair price.
Answer: (a) $197,500
(b) $ 189,500
Explanation:
Given : The marginal cost function : 
To find the cost function, we need to integrate the above function with respect to x.
Now, the additional cost incurred in dollars when production is increased from 100 units to 150 units will be:-
![\int^{150}_{100}\ C'(x)\ dx\\\\=\int^{150}_{100} (4000-0.4x)\ dx\\\\=[4000x-\dfrac{0.4x^2}{2}]^{150}_{100}\\\\=[4000(150)-\dfrac{0.4(150)^2}{2}-4000(100)+\dfrac{0.4(100)^2}{2}]\\\\=[600000-4500-400000+2000]\\\\=197500](https://tex.z-dn.net/?f=%5Cint%5E%7B150%7D_%7B100%7D%5C%20C%27%28x%29%5C%20dx%5C%5C%5C%5C%3D%5Cint%5E%7B150%7D_%7B100%7D%20%284000-0.4x%29%5C%20dx%5C%5C%5C%5C%3D%5B4000x-%5Cdfrac%7B0.4x%5E2%7D%7B2%7D%5D%5E%7B150%7D_%7B100%7D%5C%5C%5C%5C%3D%5B4000%28150%29-%5Cdfrac%7B0.4%28150%29%5E2%7D%7B2%7D-4000%28100%29%2B%5Cdfrac%7B0.4%28100%29%5E2%7D%7B2%7D%5D%5C%5C%5C%5C%3D%5B600000-4500-400000%2B2000%5D%5C%5C%5C%5C%3D197500)
Hence, the additional cost incurred in dollars when production is increased from 100 units to 150 units= $197,500
Similarly, the additional cost incurred in dollars when production is increased from 500 units to 550 units :-
![\int^{550}_{500}\ C'(x)\ dx\\\\=\int^{550}_{500} (4000-0.4x)\ dx\\\\=[4000x-\dfrac{0.4x^2}{2}]^{550}_{500}\\\\=[4000(550)-\dfrac{0.4(550)^2}{2}-4000(500)+\dfrac{0.4(500)^2}{2}]\\\\=[2200000-60500-2000000+50000]\\\\=189,500](https://tex.z-dn.net/?f=%5Cint%5E%7B550%7D_%7B500%7D%5C%20C%27%28x%29%5C%20dx%5C%5C%5C%5C%3D%5Cint%5E%7B550%7D_%7B500%7D%20%284000-0.4x%29%5C%20dx%5C%5C%5C%5C%3D%5B4000x-%5Cdfrac%7B0.4x%5E2%7D%7B2%7D%5D%5E%7B550%7D_%7B500%7D%5C%5C%5C%5C%3D%5B4000%28550%29-%5Cdfrac%7B0.4%28550%29%5E2%7D%7B2%7D-4000%28500%29%2B%5Cdfrac%7B0.4%28500%29%5E2%7D%7B2%7D%5D%5C%5C%5C%5C%3D%5B2200000-60500-2000000%2B50000%5D%5C%5C%5C%5C%3D189%2C500)
Hence, the additional cost incurred in dollars when production is increased from 500 units to 550 units = $ 189,500
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