All categories

3 years ago

Determine the value of x in the equation x+5x=5x+7

Mathematics

1 answer:

12345 [234]3 years ago

6 0

$\text{Hey there!}$

$\mathsf{Determine\ the\ value\ of\ x\ in\ the\ equation\ x+5x=5x+7.}$

$\mathsf{SIMPLIFY\ both\ sides\ of\ your\ equation}$

$\mathsf{x+5x=5x+7}$

$\mathsf{COMBINE\ your\ like\ terms}$

$\mathsf{(x+5x)=(5x+7)}$

$\mathsf{The\ RIGHT\ side\ DOES\ NOT\ have\ any\ like\ terms\ so\ we\ can}\\\mathsf{can\ leave\ alone}$

$\mathsf{x+5x= 6x}$

$\mathsf{Your\ new\ equation: 6x=5x+7}$

$\mathsf{SUBTRACT\ by\ 5x\ on\ your\ sides}$

$\mathsf{6x-5x}\\\mathsf{=}\\\mathsf{7-5x}$

$\mathsf{SOLVE\ your\ equation\ above\uparrow}$

$\mathsf{If\ you\ SOLVED\ correctly\ you\ SHOULD\ have\ the\ VALUE\ of\ x}$

$\boxed{\boxed{\mathsf{Thus\ your\ answer\ is\ x=7}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\dfrac{\frak{LoveYourselfFirst}}{:)}$

You might be interested in

Why is 3 + (−5) equal to −2?

algol13

Because it is 5 units to the left of 3 on a horizontal number line

4 0

3 years ago

What is the product of the sum of eight and two and the difference between eight and two? Show all work.

meriva

<h2>Answer:</h2><h3>=60</h3><h2>Step-by-step explanation:</h2><h3>=Solution:</h3><h3> (8+2) × (8-2)</h3><h3> =10×6</h3><h3> =60#</h3>

3 0

2 years ago

Topic: The Quadratic Formula

Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

$x= \frac{-b +- \sqrt{b^2-4ac} }{2a}$

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² = x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

$x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\= -4 or 1$

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

$x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\$

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

$x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2$

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

7 0

3 years ago

Who ever gets it right first gets brainliest

sleet_krkn [62]

Answer: Playing chess with Katie cause who'd play chess by themself right?

Step-by-step explanation:

7 0

3 years ago

Ng 20-21

Lisa [10]

you would spend $30

Step-by-step explanation:

if 20 calculator cost 120 then you would divide 20 by 120 which would give you 6 dollars per calculator then you would multiply that by 5 which would give you a $30 for five calculators.

4 0

3 years ago

Read 2 more answers