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2 years ago

8

What is the probability of choosing an outfit from a green shirt,blue shirtor a red shirt,and a black short or blue pants?What i

s the probability of choosing a vowel from the word counting and a consanant from the word prime.

1 answer:

amid [387]2 years ago

7 0

Don’t understand what your asking in the first one. Choosing a vowel out of the word counting would be 3/8. And picking a consonant out of the word prime would be 3/5.

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In all, 1000 students took a statistics exam worth 150 points. The first quartile (or Q1) for all 1000 scores is 90 points. Abou

Brums [2.3K]

Answer:

The number of students who scored more than 90 points is 750.

Step-by-step explanation:

Quartiles are statistical measures that the divide the data into four groups.

The first quartile (Q₁) indicates that 25% of the observation are less than or equal to Q₁.

The second quartile (Q₂) indicates that 50% of the observation are less than or equal to Q₂.

The third quartile (Q₃) indicates that 75% of the observation are less than or equal to Q₃.

It is provided that the first quartile is at 90 points.

That is, P (X ≤ 90) = 0.25.

The probability that a student scores more than 90 points is:

P (X > 90) = 1 - P (X ≤ 90)

= 1 - 0.25

= 0.75

The number of students who scored more than 90 points is: 1000 × 0.75 = 750.

4 0

2 years ago

Read 2 more answers

What is the equation for this line

pogonyaev

The equation of the line is $y=\frac{-1}{5} x-\frac{21}{5}$ .

Solution:

The points on the line are (–6, –3) and (4, –5).

$x_{1}=-6, y_{1}=-3, x_{2}=4, y_{2}=-5$

Slope of the line:

$$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$$m=\frac{-5-(-3)}{4-(-6)}$

$$m=\frac{-5+3}{4+6}$

$$m=\frac{-2}{10}$

$$m=\frac{-1}{5}$

Point-slope formula:

$y-y_{1}=m\left(x-x_{1}\right)$

$$y-(-3)=\frac{-1}{5}(x-(-6))$

$$y+3=\frac{-1}{5}(x+6)$

$$y+3=\frac{-1}{5} x-\frac{6}{5}$

Subtract 3 from both sides of the equation.

$$y=\frac{-1}{5} x-\frac{21}{5}$

The equation of the line is $y=\frac{-1}{5} x-\frac{21}{5}$ .

6 0

3 years ago

A piece of wire 23 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria

AURORKA [14]

Answer:

For maximum area, all of the wire should be used to construct the square.

The minimum total area is obtained when length of the wire is 10m

Step-by-step explanation:

For maximum, we use the whole length

For minimum,

supposed the x length was used for the square,

the length of the side of the square = x/4m

Area = $\frac{x^{2} }{16}$

For the equilateral triangle, the length of the side = $\frac{23 - x}{3}$

Area = $\frac{\sqrt{3} }{4} a^{2} = \frac{\sqrt{3} }{4} (\frac{23 - x}{3} )^{2}$

Total Area = $\frac{x^{2} }{16}$ + $\frac{\sqrt{3} }{36} (23-x)^{2}$

$\frac{dA}{dx} = \frac{x}{8} - \frac{\sqrt{3} }{18} (23 - x)\\$

$\frac{d^{2}A }{dx^{2} } = \frac{1}{8} + \frac{\sqrt{3} }{18} > 0$ , therefore it is minimum

$\frac{dA}{dx} = 0 \\\\$

$\frac{x}{8} - \frac{\sqrt{3} }{18} (23 - x) = 0\\$

x = 10.00m

3 0

2 years ago

Read 2 more answers

Please help i will give extra points

belka [17]

Answer:

-63

Step-by-step explanation:

(-25+4^2) * 7

(-25+16) * 7

-9*7=-63

6 0

2 years ago

Solve the equation please!

yKpoI14uk [10]

Answer:

z=-60

Step-by-step explanation:

1/6z=-10

z=-10×6

z=-60

6 0

2 years ago

Read 2 more answers