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ivolga24 [154]
3 years ago
7

Given f(x) = -2x2 + 5x - 1 and g(x) = 3x + 4 determine a simplified

Computers and Technology
1 answer:
lukranit [14]3 years ago
7 0

Answer:

-6x^4 + 7x^3 + 17x^2 -4x

Explanation:

( f x g )( x )

Substitute

[( -2x^2 + 5x -1 )( 3x + 4 )]( x )

Use the Distributive Property

[-2x^2( 3x) + 5x( 3x) - 1( 3x) -2x^2( 4) + 5x (4) -1 (4)] (x)

Simplify

( -6x^3 + 7x^2 + 17x -4)(x)

Distributive Property

-6x^4 + 7x^3 + 17x^2 -4x

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Create a class called Clock to represent a Clock. It should have three private instance variables: An int for the hours, an int
Anvisha [2.4K]

Answer:

public class Clock

{

private int hr; //store hours

private int min;  //store minutes

private int sec; //store seconds

public Clock ()

{

 setTime (0, 0, 0);

}

public Clock (int hours, int minutes, int seconds)

{

 setTime (hours, minutes, seconds);

}

public void setTime (int hours, int minutes, int seconds)

{

 if (0 <= hours && hours < 24)

      hr = hours;

 else

      hr = 0;

 

 if (0 <= minutes && minutes < 60)

      min = minutes;

 else

      min = 0;

 

 if (0 <= seconds && seconds < 60)

      sec = seconds;

 else

      sec = 0;

}

 

 //Method to return the hours

public int getHours ( )

{

 return hr;

}

 //Method to return the minutes

public int getMinutes ( )

{

 return min;

}

 //Method to return the seconds

public int getSeconds ( )

{

 return sec;

}

public void printTime ( )

{

 if (hr < 10)

      System.out.print ("0");

 System.out.print (hr + ":");

 if (min < 10)

      System.out.print ("0");

 System.out.print (min + ":");

 if (sec < 10)

      System.out.print ("0");

 System.out.print (sec);

}

 

 //The time is incremented by one second

 //If the before-increment time is 23:59:59, the time

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public void incrementSeconds ( )

{

 sec++;

 

 if (sec > 59)

 {

  sec = 0;

  incrementMinutes ( );  //increment minutes

 }

}

 ///The time is incremented by one minute

 //If the before-increment time is 23:59:53, the time

 //is reset to 00:00:53

public void incrementMinutes ( )

{

 min++;

 

if (min > 59)

 {

  min = 0;

  incrementHours ( );  //increment hours

 }

}

public void incrementHours ( )

{

 hr++;

 

 if (hr > 23)

     hr = 0;

}

public boolean equals (Clock otherClock)

{

 return (hr == otherClock.hr

  && min == otherClock.min

   && sec == otherClock.sec);

}

}

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2 years ago
How do you delete answers on Brain.ly?
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It is a JavaScript property used to call a function after a specified time, in milliseconds​
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Answer:

setTimeout is a native JavaScript function (although it can be used with a library such as jQuery, as we'll see later on), which calls a function or executes a code snippet after a specified delay (in milliseconds).

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Hubs are very simple devices that connect network components, sending a packet of data to all other connected devices.

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Answer:

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